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Find the mean of the data summarized in the given frequency distribution. Compare the computed mean to the actual mean of 52.9 degrees. Low Temperature (F) 40-44 45-49 50-54 55-59 60-64 Frequency 1 6 10 5 3 The mean of the frequency distribution is degrees. (Round to the nearest tenth as needed.)

Find the mean of the data summarized in the given frequency distribution. Compare the computed mean to the actual mean of 52.9 degrees. Low Temperature (F) 40-44 45-49 50-54 55-59 60-64 Frequency 1 6 10 5 3 The mean of the frequency distribution is degrees. (Round to the nearest tenth as needed.)

Holt Mcdougal Larson Pre-algebra: Student Edition 2012
Holt Mcdougal Larson Pre-algebra: Student Edition 2012
1st Edition
ISBN:9780547587776
Author:HOLT MCDOUGAL
Publisher:HOLT MCDOUGAL
Chapter11: Data Analysis And Probability
Section11.2: Box-and-whisker Plots
Problem 1E
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**Question:** Which of the following best describes the relationship between the computed mean and the actual mean? - **A.** The computed mean is close to the actual mean because the difference between the means is less than 5%. - **B.** The computed mean is close to the actual mean because the difference between the means is more than 5%. - **C.** The computed mean is not close to the actual mean because the difference between the means is more than 5%. - **D.** The computed mean is not close to the actual mean because the difference between the means is less than 5%.
Transcribed Image Text:**Question:** Which of the following best describes the relationship between the computed mean and the actual mean? - **A.** The computed mean is close to the actual mean because the difference between the means is less than 5%. - **B.** The computed mean is close to the actual mean because the difference between the means is more than 5%. - **C.** The computed mean is not close to the actual mean because the difference between the means is more than 5%. - **D.** The computed mean is not close to the actual mean because the difference between the means is less than 5%.
### Frequency Distribution of Low Temperatures Find the mean of the data summarized in the given frequency distribution. Compare the computed mean to the actual mean of 52.9 degrees. #### Data Table - **Low Temperature (°F):** - 40 – 44 - 45 – 49 - 50 – 54 - 55 – 59 - 60 – 64 - **Frequency:** - 1 - 6 - 10 - 5 - 3 --- The mean of the frequency distribution is [ ] degrees. (Round to the nearest tenth as needed.) --- ### Instructions to Calculate the Mean: 1. **Identify the Midpoint of Each Interval:** Calculate the midpoint for each temperature range: - Midpoint of 40-44: (40 + 44)/2 = 42 - Midpoint of 45-49: (45 + 49)/2 = 47 - Midpoint of 50-54: (50 + 54)/2 = 52 - Midpoint of 55-59: (55 + 59)/2 = 57 - Midpoint of 60-64: (60 + 64)/2 = 62 2. **Multiply Each Midpoint by its Frequency:** - 42 × 1 = 42 - 47 × 6 = 282 - 52 × 10 = 520 - 57 × 5 = 285 - 62 × 3 = 186 3. **Add all Products Together:** 42 + 282 + 520 + 285 + 186 = 1315 4. **Divide by the Total Frequency:** Total frequency = 1 + 6 + 10 + 5 + 3 = 25 5. **Mean Calculation:** Mean = 1315 / 25 = 52.6 The mean of the frequency distribution is 52.6 degrees, which can be compared to the actual mean of 52.9 degrees.
Transcribed Image Text:### Frequency Distribution of Low Temperatures Find the mean of the data summarized in the given frequency distribution. Compare the computed mean to the actual mean of 52.9 degrees. #### Data Table - **Low Temperature (°F):** - 40 – 44 - 45 – 49 - 50 – 54 - 55 – 59 - 60 – 64 - **Frequency:** - 1 - 6 - 10 - 5 - 3 --- The mean of the frequency distribution is [ ] degrees. (Round to the nearest tenth as needed.) --- ### Instructions to Calculate the Mean: 1. **Identify the Midpoint of Each Interval:** Calculate the midpoint for each temperature range: - Midpoint of 40-44: (40 + 44)/2 = 42 - Midpoint of 45-49: (45 + 49)/2 = 47 - Midpoint of 50-54: (50 + 54)/2 = 52 - Midpoint of 55-59: (55 + 59)/2 = 57 - Midpoint of 60-64: (60 + 64)/2 = 62 2. **Multiply Each Midpoint by its Frequency:** - 42 × 1 = 42 - 47 × 6 = 282 - 52 × 10 = 520 - 57 × 5 = 285 - 62 × 3 = 186 3. **Add all Products Together:** 42 + 282 + 520 + 285 + 186 = 1315 4. **Divide by the Total Frequency:** Total frequency = 1 + 6 + 10 + 5 + 3 = 25 5. **Mean Calculation:** Mean = 1315 / 25 = 52.6 The mean of the frequency distribution is 52.6 degrees, which can be compared to the actual mean of 52.9 degrees.
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