Find the magnitude and direction of the resultant force and moment at A
Find the magnitude and direction of the resultant force and moment at A
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
Related questions
Question
Correct the data from the table. I don't know the correct way when I have to put the signs when it is cos, sin, force, and couples data.
![1-2
2) Find the magnitude and direction of the resultant force and moment at A
1"
-75
-150lb
1"
30--129-90
-150
200 0
FORCE e F= F.Cos( Ⓒ )
lbs
R =
OR
MR =
-300lb
60
А ПР
=
200
-75
200lb
Ry =
300lb
F, = F.Sin(e)
0
-129.90
-129.90*3.
-389.7 16
MR.
A
M₂=Fxd
Forces
Couples
200x2=4001 4.24× 300 =
1272.79
+MA
Couple=√(3)+(332)
= 4.24
= 10.3 +1272,79 = 1283.09 16
-MA
J](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F32599b3d-5f12-46d4-a56d-3b2a99f57c73%2Fd91864dc-2a19-4981-89b0-428a4410f6ed%2Fsb8rm5d_processed.jpeg&w=3840&q=75)
Transcribed Image Text:1-2
2) Find the magnitude and direction of the resultant force and moment at A
1"
-75
-150lb
1"
30--129-90
-150
200 0
FORCE e F= F.Cos( Ⓒ )
lbs
R =
OR
MR =
-300lb
60
А ПР
=
200
-75
200lb
Ry =
300lb
F, = F.Sin(e)
0
-129.90
-129.90*3.
-389.7 16
MR.
A
M₂=Fxd
Forces
Couples
200x2=4001 4.24× 300 =
1272.79
+MA
Couple=√(3)+(332)
= 4.24
= 10.3 +1272,79 = 1283.09 16
-MA
J
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