Find the magnitude and direction (in degrees) of the vector. (Assume 0° ≤ 0 < 360°.) 2 1- (- √/²₁ - √₂) = 6 |v| = 0 = O

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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**Problem Statement:**

Find the magnitude and direction (in degrees) of the vector. (Assume \(0^\circ \leq \theta < 360^\circ\).)

**Vector:**

\[ \mathbf{v} = \left\langle -\frac{\sqrt{2}}{6}, -\frac{\sqrt{2}}{6} \right\rangle \]

**Magnitude:**

\[ |\mathbf{v}| = \_\_\_ \]

**Direction:**

\[ \theta = \_\_\_^\circ \]
Transcribed Image Text:**Problem Statement:** Find the magnitude and direction (in degrees) of the vector. (Assume \(0^\circ \leq \theta < 360^\circ\).) **Vector:** \[ \mathbf{v} = \left\langle -\frac{\sqrt{2}}{6}, -\frac{\sqrt{2}}{6} \right\rangle \] **Magnitude:** \[ |\mathbf{v}| = \_\_\_ \] **Direction:** \[ \theta = \_\_\_^\circ \]
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