Homework Help is Here – Start Your Trial Now!
Science
Advanced Physics
Find the magnetic flux density due to the given current density everywhere: 4r² J(r) = Ho 0 5 1

Find the magnetic flux density due to the given current density everywhere: 4r² J(r) = Ho 0 5 1

icon
Related questions
Question

please solve Q1 with a detailed answer 

1) Find the magnetic flux density due to the given current density everywhere: 47² J(r)= Ho 0 " 1<r<2 otherwise (A/m²) 2) The magnetic field intensity is given as Ħ=-yâ¸+xâ¸(A/m) in the z=0 plane. Determine the current density that creates this magnetic field intensity. 3) A solenoid with radius a, length L and N turns of wire is given. A current of I is flowing through the wire. In the core of the solenoid there is a magnetic material of permeability μ = μr (H/m). Remembering that the magnetic field intensity within the solenoid is IN Ā -â. (A/m), L Determine: a. the magnetic flux density in the core of the solenoid. b. the total magnetic flux flowing through the cross-section of the solenoid. c. the self-inductance of the solenoid for a length L.
Transcribed Image Text:1) Find the magnetic flux density due to the given current density everywhere: 47² J(r)= Ho 0 " 1<r<2 otherwise (A/m²) 2) The magnetic field intensity is given as Ħ=-yâ¸+xâ¸(A/m) in the z=0 plane. Determine the current density that creates this magnetic field intensity. 3) A solenoid with radius a, length L and N turns of wire is given. A current of I is flowing through the wire. In the core of the solenoid there is a magnetic material of permeability μ = μr (H/m). Remembering that the magnetic field intensity within the solenoid is IN Ā -â. (A/m), L Determine: a. the magnetic flux density in the core of the solenoid. b. the total magnetic flux flowing through the cross-section of the solenoid. c. the self-inductance of the solenoid for a length L.
Expert Solution
steps

Step by step

Solved in 5 steps with 8 images

SEE SOLUTIONCheck out a sample Q&A here
Blurred answer