Find the Maclaurin polynomials of orders n = 0,1,2,3, and 4, and then find the nth Maclaurin polynomials, p,(x) for the function in sigma notation for f(x) = e* Choose the correct answer. O Po(x) = 1, p1(x) = 1+ ax, p2(x) = 1 + ax + ax, p3(x) = 1+ ax + ax +ax, P4(x) = 1+ ax + ax +a'x +a*x, p(x) = ax Po(x) = 1, p1(x) = 1- ax, p2(x) = 1 – ax + P3 (x) = 1 – ax + 2! 2! ax P4(x) = 1 - ax + 2! 3! axt 3! Pn(x) = 4! k! a-r Po(x) = 1, p1(x) = 1 – ax, p2(x) = 1 – ax + P3(x) = 1 – ax + ax P4(x) = 1- ax + a 4 Pa(x) = (-1 Po(x) = 1, p1(x) = 1 + ax, p2(x) = 1 + ax + a²x² P3(x) = 1 + ax + P4(x) = 1 + ax +- 3 4 Pa(x) = Po(x) = 1, p1(x) = 1 + ax, p2(x) = 1 + ax + 2! P3(x) = 1 + ax + ax P4(x) = 1 + ax + 2! Pa(x) = 4! 3!

Calculus: Early Transcendentals
8th Edition
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Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Find the Maclaurin polynomials of orders n = 0,1,2,3, and 4, and then find the nth Maclaurin polynomials, p, (x) for the function in
sigma notation for
fx) = e*
Choose the correct answer.
O po(x) = 1, p1(x) = 1+ ax, p2(x) = 1 + ax + ax, p3(x) = 1 + ax + ax + ax,
p4(x) = 1+ ax + ax +ax +a*, p.x) 3D
Po(x) = 1, pi (x) = 1- ax, p2(x) = 1 - ax+
2!
a²x²
- P3(x) = 1 – ax +
2!
3!
ax
P4(x) = 1- ax +
2!
P(x) =
3!
4!
k!
Po(x) = 1, p1(x) = 1- ax, P2(x) = 1 – ax + P3(x) = 1 – ax +
a-x
2
a-x
P4(x) = 1- ax +
ΣΗ
3
Pa(x) =
14
Po(x) = 1, p1(x) = 1 + ax, p2(x) = 1 + ax + *
ax
P3(x) = 1 + ax +
P4(x) = 1 + ax + -
121
Pa(x) =
4
a²x²
12 P3(x) = 1+ ax +.
a
Po(x) = 1, p1(x) = 1 + ax, p2 (x) = 1 + ax +
ax a°x
3!
P4x) = 1 + ax +
2!
P. (x) =
4!
k!
Transcribed Image Text:Find the Maclaurin polynomials of orders n = 0,1,2,3, and 4, and then find the nth Maclaurin polynomials, p, (x) for the function in sigma notation for fx) = e* Choose the correct answer. O po(x) = 1, p1(x) = 1+ ax, p2(x) = 1 + ax + ax, p3(x) = 1 + ax + ax + ax, p4(x) = 1+ ax + ax +ax +a*, p.x) 3D Po(x) = 1, pi (x) = 1- ax, p2(x) = 1 - ax+ 2! a²x² - P3(x) = 1 – ax + 2! 3! ax P4(x) = 1- ax + 2! P(x) = 3! 4! k! Po(x) = 1, p1(x) = 1- ax, P2(x) = 1 – ax + P3(x) = 1 – ax + a-x 2 a-x P4(x) = 1- ax + ΣΗ 3 Pa(x) = 14 Po(x) = 1, p1(x) = 1 + ax, p2(x) = 1 + ax + * ax P3(x) = 1 + ax + P4(x) = 1 + ax + - 121 Pa(x) = 4 a²x² 12 P3(x) = 1+ ax +. a Po(x) = 1, p1(x) = 1 + ax, p2 (x) = 1 + ax + ax a°x 3! P4x) = 1 + ax + 2! P. (x) = 4! k!
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