Find the Maclaurin polynomials of orders n = 0,1,2,3, and 4, and then find the nth Maclaurin polynomials, P.(x) for the function in sigma notation for f() = Choose the correct answer. O po(x) = 1, p1 (x) = 1 + ax, p2(x) = 1 + ax + a'x, p3(x) = 1+ ax+ a + a'x. p4(x) = 1 + ax + a²x +a'x' +ax, pa(x) = Eax* O. Po(x) = 1, p1(x) = 1- ax, p2(x) = 1- ax + a'x 2! P3(x) = 1- ax + 2! 3! ax ax ax P4(x) = 1 – ax+ 2! 4! Pn(x) = k=0 3! k! ax ax ax? Po(x) = 1, p1(x) = 1 – ax, p2(x) = 1 – ax + ax ax a 2 P3(x) = 1 – ax + P4(x) = 1– ax + 4 Pn(x) = ku0 Po(x) = 1, p1(x) = 1 + ax, p2(x) = 1 + ax + ax? , P3(x) = 1+ ax + a²x? P4(x) = 1 + ax + ax atx Pn(x) = k=0 3 4 ax 21: P3(x) =1+ ax + atx Po(x) = 1, p1(x) = 1 + ax, p2(x) = 1 + ax + ax 2! P4(x) = 1+ ax+ 2! ax ax atx 3! 4! Pn(x) = k!

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Find the Maclaurin polynomials of orders n = 0,1,2,3, and 4, and then find the nth Maclaurin polynomials, p.(x) for the function in
sigma notation for
f) =
Choose the correct answer.
O po(x) = 1, p1 (x) = 1 + ax, p2(x) = 1+ ax + a'x, p3(x) = 1 + ax + a*x² + a°x,
pA(x) = 1 + ax + a²r +ax +a*x*, p,(x) =
ax?
Po(x) = 1, p1(x) = 1- ax, p2(x) 1- ar +
ax
P3 (x) = 1 - ax +
2!
a'x
2!
3!
ax
P4(x) = 1- ax +
2!
(-1)
k!
3!
4! Pn (x) =
Po(x) = 1, p1 (x) = 1- ax, p2(x) = 1- ax +
P3(x) = 1– ax +
2
ax ax?
atx
Pn (x) =
P4(x) = 1– ax +
3
4
ax
Po(x) = 1, p1(x) = 1 + ax, p2(x) = 1+ ax +
P3(x) = 1+ ax +
2
ax
P4(x) = 1 + ax + -
ax
atx
4 Pn (x) =
3
k=0
ax
P3 (x) = 1+ ax +
ax
a'x
3!
Po(x) = 1, p1(x) = 1 + ax, p2(x) = 1+ ax +
2!
atx
k!
2!
a²x
P4(x) = 1+ ax+
2!
ax
atx
3!
4! P(x)
Transcribed Image Text:Find the Maclaurin polynomials of orders n = 0,1,2,3, and 4, and then find the nth Maclaurin polynomials, p.(x) for the function in sigma notation for f) = Choose the correct answer. O po(x) = 1, p1 (x) = 1 + ax, p2(x) = 1+ ax + a'x, p3(x) = 1 + ax + a*x² + a°x, pA(x) = 1 + ax + a²r +ax +a*x*, p,(x) = ax? Po(x) = 1, p1(x) = 1- ax, p2(x) 1- ar + ax P3 (x) = 1 - ax + 2! a'x 2! 3! ax P4(x) = 1- ax + 2! (-1) k! 3! 4! Pn (x) = Po(x) = 1, p1 (x) = 1- ax, p2(x) = 1- ax + P3(x) = 1– ax + 2 ax ax? atx Pn (x) = P4(x) = 1– ax + 3 4 ax Po(x) = 1, p1(x) = 1 + ax, p2(x) = 1+ ax + P3(x) = 1+ ax + 2 ax P4(x) = 1 + ax + - ax atx 4 Pn (x) = 3 k=0 ax P3 (x) = 1+ ax + ax a'x 3! Po(x) = 1, p1(x) = 1 + ax, p2(x) = 1+ ax + 2! atx k! 2! a²x P4(x) = 1+ ax+ 2! ax atx 3! 4! P(x)
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