thank you for your help I'm having troiuble **Find the logarithm:**\[\log_6 \left( \frac{1}{1296} \right) = \, \text{[Input Box]}\]**Add Work** [Button]---**Explanation:**This exercise asks the user to calculate the logarithm with base 6 of the fraction $\frac{1}{1296}$. The input box is provided for the user to enter their answer. The "Add Work" button suggests that there is an option to show or enter the steps used to arrive at the solution.

Name: thank you for your help I'm having troiuble **Find the logarithm:**\[\
Uploaded: 2024-03-20T07:06:41.000Z
Channel: Bartleby
Description: thank you for your help I'm having troiuble **Find the logarithm:**\[\log_6 \left( \frac{1}{1296} \right) = \, \text{[Input Box]}\]**Add Work** [Button]---**Explanation:**This exercise asks the user to calculate the logarithm with base 6 of the fract

Answered: Find the logarithm. 1 logs 1296

Algebra and Trigonometry (6th Edition)

6th Edition

ISBN:9780134463216

Author:Robert F. Blitzer

Publisher:Robert F. Blitzer

ChapterP: Prerequisites: Fundamental Concepts Of Algebra

Section: Chapter Questions

Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...

See similar textbooks

Related questions

Concept explainers

Topic Video

Question

thank you for your help I'm having troiuble

**Find the logarithm:**

\[
\log_6 \left( \frac{1}{1296} \right) = \, \text{[Input Box]}
\]

**Add Work** [Button]

---

**Explanation:**

This exercise asks the user to calculate the logarithm with base 6 of the fraction $\frac{1}{1296}$. The input box is provided for the user to enter their answer. The "Add Work" button suggests that there is an option to show or enter the steps used to arrive at the solution.

Expert Solution

Step 1

Given: $\log_{6} (\frac{1}{1296})$

Step 2

Explanation:

$\log_{6} (\frac{1}{1296}) = \log_{6} {(\frac{1}{6})}^{4} = \log_{6} {(6)}^{- 4} = - 4 \log_{6} (6) [∵ \log {(a)}^{b} = b \log (a)] = - 4 [∵ \log_{a} a = 1]$

Step by step

Solved in 3 steps

Knowledge Booster

$Discrete Probability Distributions$

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, algebra and related others by exploring similar questions and additional content below.

Similar questions