Find the instantaneous velocity of the particle described in the figure below at the x(m) 10 8- 6 4 (s) 1 4 6 -2 -4 t = 1.3 s m/s (a) t = 3.1 s m/s (b) t = 4.8 s m/s (c) (d) t = 7.1 s m/s
Find the instantaneous velocity of the particle described in the figure below at the x(m) 10 8- 6 4 (s) 1 4 6 -2 -4 t = 1.3 s m/s (a) t = 3.1 s m/s (b) t = 4.8 s m/s (c) (d) t = 7.1 s m/s
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Question
![Find the instantaneous velocity of the particle described in the figure below at the follow
x(m)
10
6.
4
2
(s)
4
6
-2
-4
(a)
t = 1.3 s
m/s
(b)
t = 3.1 s
m/s
(c) t = 4.8 s
m/s
(d)
t = 7.1 s
m/s](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ff82676c5-2454-480e-a2f2-64b4ed4c2c54%2F82f5d3e8-cb8a-44e2-bf80-6934eda72cd8%2Fkwh21hf_processed.png&w=3840&q=75)
Transcribed Image Text:Find the instantaneous velocity of the particle described in the figure below at the follow
x(m)
10
6.
4
2
(s)
4
6
-2
-4
(a)
t = 1.3 s
m/s
(b)
t = 3.1 s
m/s
(c) t = 4.8 s
m/s
(d)
t = 7.1 s
m/s
Expert Solution
![](/static/compass_v2/shared-icons/check-mark.png)
Step 1
Given is position vs time Graph
Instantaneous velocity (v)= slope of position vs time graph at that instant
= dx/dt
(a) t= 1.3 s
v = dx/dt
=10/2 = 5 m/s
Slope is same for t=0 to t= 2 s
(b) t = 3.1 s
v = dx /dt = ∆x/∆t
= (5-10)/(4-2)
= -5/2 = - 2.5m/s
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