Find the impulse response of the system with the following transfer function: Z z² + 3z + 2 Then compute the response of the system to a discrete unit step change in the input. G(z) =
Find the impulse response of the system with the following transfer function: Z z² + 3z + 2 Then compute the response of the system to a discrete unit step change in the input. G(z) =
Introductory Circuit Analysis (13th Edition)
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ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
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![Find the impulse response of the system with the following transfer function:
Z
z² + 3z + 2
Then compute the response of the system to a discrete unit step change in the input.
G(z) =](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F563edda4-dfc7-48fd-8e0c-ee442ed6367a%2F27ff1c91-a2cb-4ec3-bded-f4a265458dda%2Fco2obij_processed.png&w=3840&q=75)
Transcribed Image Text:Find the impulse response of the system with the following transfer function:
Z
z² + 3z + 2
Then compute the response of the system to a discrete unit step change in the input.
G(z) =
![9:27
个
bartleby.com/questior
#
Step 2: Calculation of impulse response
Z
⇒ G (2) = Z²+3Z+2
G(Z) =
*
Y(Z)
U(Z)
# The impulse responc g(n)
for the system by using inverse
Z-transform of h(z)
G(Z) =
G(Z)
Z
* B
A
Z=-2
Z=-1
G(z)=
Z
⇒ b (z) =
=
Solution
Z
z²+3Z+2=
A
Z+2
-2+1
1
2-1
+
-1
Z+2
Z
2+1
B
2+1
+
-1
1
-
#s(n) = (-1)³ αu (n) - (-2)" u (n)
Vo)) LTE+
LTE1 41 .Il LTE2 .1|| 48%
anu (n) Z₁T) +
Z.T.
+
1
Z+1
Z
(Z+2) (Z+1)
1-97-1
Z
Z+2
using inverse z-transform both side,
[using
(a) u (n) Z., Z
z+a
((
"Z"² transform formula
fraction
Practial
rule]
The impulse response of the given
|||
2
z-a
12
<](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F563edda4-dfc7-48fd-8e0c-ee442ed6367a%2F27ff1c91-a2cb-4ec3-bded-f4a265458dda%2Fllcoktb_processed.jpeg&w=3840&q=75)
Transcribed Image Text:9:27
个
bartleby.com/questior
#
Step 2: Calculation of impulse response
Z
⇒ G (2) = Z²+3Z+2
G(Z) =
*
Y(Z)
U(Z)
# The impulse responc g(n)
for the system by using inverse
Z-transform of h(z)
G(Z) =
G(Z)
Z
* B
A
Z=-2
Z=-1
G(z)=
Z
⇒ b (z) =
=
Solution
Z
z²+3Z+2=
A
Z+2
-2+1
1
2-1
+
-1
Z+2
Z
2+1
B
2+1
+
-1
1
-
#s(n) = (-1)³ αu (n) - (-2)" u (n)
Vo)) LTE+
LTE1 41 .Il LTE2 .1|| 48%
anu (n) Z₁T) +
Z.T.
+
1
Z+1
Z
(Z+2) (Z+1)
1-97-1
Z
Z+2
using inverse z-transform both side,
[using
(a) u (n) Z., Z
z+a
((
"Z"² transform formula
fraction
Practial
rule]
The impulse response of the given
|||
2
z-a
12
<
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