Find the height of a satellite from the surface of the earth whose critical velocity is 5 km/s (G = 6.67 × 10-¹¹ Nm²/ kg, mass density of earth m = 6 x 1024 kg and radius of earth r = 6400 km).
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Q: Gravitational constant
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- (a) Calculate the distance from the Earth's surface of the point which the gravitational field strength is zero, given the following data: Distance between the Earth and the Moon = 384 000 km; Mass of the Earth = 5.98 x 10^24 kg; Mass of the Moon = 7.35 x 10^22 kg; Radius of the Earth = 6.37 x 10^6 m (b) If a small mass is placed at this point, does is receive gravity force? Is the gravitational potential energy at this point equal to 0? Explain your answer.Needs Complete solution with 100 % accuracy.Astronomical observations of our Milky Way galaxy indicate that it has a mass of about 8 ✕ 1011 solar masses. A star orbiting near the galaxy's periphery is 6.0 ✕ 104 light years from its center. What should the orbital period (in y) of that star be?
- When a falling meteor is at a distance 3.58times the radius of the Earth above theEarth’s surface, what is its free-fall acceleration? The acceleration of gravity is9.8 m/s squared. , the universal gravitational constant is 6.67259×10−11 N · m2/kg2 and the Earth’sradius is 6.37 × 106 m. Answer in units of m/s 2.A 750-kg satellite is in a circular orbit about Earth at a height above Earth equal to Earth's mean radius. (a) Find the satellite's orbital speed. 1768.95 × Your response differs from the correct answer by more than 10%. Double check your calculations. m/s (b) Find the period of its revolution. 12.576 Your response differs from the correct answer by more than 100%. h (c) Find the gravitational force acting on it. 114.11 × Your response differs significantly from the correct answer. Rework your solution from the beginning and check each step carefully. NA spacecraft is in a circular orbit around the planet kerbin at an altitude of 100 km. the radium of kerbin is 600km and the planet has a mass of M = 5.29*10^22kg. The universal gravitational constant is G = 6.67*10^-11 Write parametric equations for the position, velocity and acceleration vectors of the spacecraft in its orbital plane.
- A communication satellite appears stationary from a place on the equator. Find the height of the satellite from the surface of the earth. G = 6.7 x 10-¹¹ M. K. S. units. Mass of earth × = 6 × 10²¹ kg, Radius of earth = 64000 km.An artificial satellite is in a circular orbit 5.50×102 km from the surface of a planet of radius 4.50×103 km. The period of revolution of the satellite around the planet is 4.00 hours. What is the average density ?avg of the planet?A satellite is orbiting the earth in low orbit (160 km above the surface of the earth). If the universal gravitational constant is 6.67 x 10^-11 m^3/kg x s^2 the mass of the earth is 5.972 x 10^24 kg and the radius of the earth is 6371 km, what speed must the satellite travel in order to maintain the low earth orbit?
- Physics A white dwarf is the remnant core of a previous star < 8 solar masses that has about the mass of the Sun but the radius of the Earth. What would be (1) the orbital speed and (2) the orbital period for a spacecraft in orbit just above the surface of the white dwarf?The density of Planet Y in the previous problem is Show the entire calculation. Calculation: The universal gravitational -11 3 -1 -2 constant is 6.67430*10 m kg s . Planet Y has a radius of 5360km or 5.360*10 m and a mass of 4.56*10²3 kg. On this planet, a rock falls vertically down from a cliff overhang to the ground. The height of the cliff is 86m. The time it M takes the rock to fall from the overhang to the ground is Show the entire calculation. Calculation: g = G*- The density O R of Planet Y in the previous problem is Show the entire calculation. Calculation: