Find the height of a satellite from the surface of the earth whose critical velocity is 5 km/s (G = 6.67 × 10-¹¹ Nm²/ kg, mass density of earth m = 6 x 1024 kg and radius of earth r = 6400 km).
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Step by step
Solved in 2 steps
- (a) Calculate the distance from the Earth's surface of the point which the gravitational field strength is zero, given the following data: Distance between the Earth and the Moon = 384 000 km; Mass of the Earth = 5.98 x 10^24 kg; Mass of the Moon = 7.35 x 10^22 kg; Radius of the Earth = 6.37 x 10^6 m (b) If a small mass is placed at this point, does is receive gravity force? Is the gravitational potential energy at this point equal to 0? Explain your answer.Needs Complete solution with 100 % accuracy.5
- Astronomical observations of our Milky Way galaxy indicate that it has a mass of about 8 ✕ 1011 solar masses. A star orbiting near the galaxy's periphery is 6.0 ✕ 104 light years from its center. What should the orbital period (in y) of that star be?When a falling meteor is at a distance 3.58times the radius of the Earth above theEarth’s surface, what is its free-fall acceleration? The acceleration of gravity is9.8 m/s squared. , the universal gravitational constant is 6.67259×10−11 N · m2/kg2 and the Earth’sradius is 6.37 × 106 m. Answer in units of m/s 2.A 750-kg satellite is in a circular orbit about Earth at a height above Earth equal to Earth's mean radius. (a) Find the satellite's orbital speed. 1768.95 × Your response differs from the correct answer by more than 10%. Double check your calculations. m/s (b) Find the period of its revolution. 12.576 Your response differs from the correct answer by more than 100%. h (c) Find the gravitational force acting on it. 114.11 × Your response differs significantly from the correct answer. Rework your solution from the beginning and check each step carefully. N
- A spacecraft is in a circular orbit around the planet kerbin at an altitude of 100 km. the radium of kerbin is 600km and the planet has a mass of M = 5.29*10^22kg. The universal gravitational constant is G = 6.67*10^-11 Write parametric equations for the position, velocity and acceleration vectors of the spacecraft in its orbital plane.A communication satellite appears stationary from a place on the equator. Find the height of the satellite from the surface of the earth. G = 6.7 x 10-¹¹ M. K. S. units. Mass of earth × = 6 × 10²¹ kg, Radius of earth = 64000 km.An artificial satellite is in a circular orbit 5.50×102 km from the surface of a planet of radius 4.50×103 km. The period of revolution of the satellite around the planet is 4.00 hours. What is the average density ?avg of the planet?
- A satellite is orbiting the earth in low orbit (160 km above the surface of the earth). If the universal gravitational constant is 6.67 x 10^-11 m^3/kg x s^2 the mass of the earth is 5.972 x 10^24 kg and the radius of the earth is 6371 km, what speed must the satellite travel in order to maintain the low earth orbit?Physics A white dwarf is the remnant core of a previous star < 8 solar masses that has about the mass of the Sun but the radius of the Earth. What would be (1) the orbital speed and (2) the orbital period for a spacecraft in orbit just above the surface of the white dwarf?The density of Planet Y in the previous problem is Show the entire calculation. Calculation: The universal gravitational -11 3 -1 -2 constant is 6.67430*10 m kg s . Planet Y has a radius of 5360km or 5.360*10 m and a mass of 4.56*10²3 kg. On this planet, a rock falls vertically down from a cliff overhang to the ground. The height of the cliff is 86m. The time it M takes the rock to fall from the overhang to the ground is Show the entire calculation. Calculation: g = G*- The density O R of Planet Y in the previous problem is Show the entire calculation. Calculation: