Find the general solution x = ([2, -5],[1, 2])x+ ([0], [cost]), 0Answer is : x = c1[5cos(t), 2cos (t) + sin(t)] + c2[5sin(t), -cos(t) + 2sin(t)] + [0,1/2]t*cos(t) - [5/2,1]t*sin(t)- [5/2, 1]cos(t) HOW DO I GET THIS ANSWER
Find the general solution x = ([2, -5],[1, 2])x+ ([0], [cost]), 0Answer is : x = c1[5cos(t), 2cos (t) + sin(t)] + c2[5sin(t), -cos(t) + 2sin(t)] + [0,1/2]t*cos(t) - [5/2,1]t*sin(t)- [5/2, 1]cos(t) HOW DO I GET THIS ANSWER
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
Related questions
Question
![Find the general solution x = : ([2, -5], [1, -2])x+ ([0], [cost]), 0Answer is : x = c1[5cos(t), 2cos
(t) + sin(t)] + c2[5sin(t), -cos(t) + 2sin(t)] + [0,1/2]t*cos(t) - [5/2, 1]t*sin(t) - [5/2, 1]cos(t)
HOW DO I GET THIS ANSWER
8. x'
3
c
-5
0
= (₁-2) x + (+), 0
COS
0<t<π](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F81002dc1-d729-4c3e-8798-fdc24b78397c%2F2546dc5d-65ee-452e-a44d-d8155bd34b29%2F21uzzz_processed.png&w=3840&q=75)
Transcribed Image Text:Find the general solution x = : ([2, -5], [1, -2])x+ ([0], [cost]), 0Answer is : x = c1[5cos(t), 2cos
(t) + sin(t)] + c2[5sin(t), -cos(t) + 2sin(t)] + [0,1/2]t*cos(t) - [5/2, 1]t*sin(t) - [5/2, 1]cos(t)
HOW DO I GET THIS ANSWER
8. x'
3
c
-5
0
= (₁-2) x + (+), 0
COS
0<t<π
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