SpecificHeat, CpWaterThermalThermalContent, Temperature, T Density, p Conductivity, kIbm/ft3Diffusivity, aft2/sFood%(mass)°FBtu/h-ft.°FBtu/lbm-RFruits/VegetablesApple juiceApplesApples, driedApricots, driedBananas, fresh1.51 x 10-61.47 x 10-6876862.40.3230.9228532-8652.40.2420.91041.67353.40.1271.03 x 10-60.6501.22 x 10-61.51 × 10-643.67382.40.2170.662764161.20.2780.856Broccoli2135.00.223|1.42 x 10-6Cherries, freshFigsGrape juice9232-8665.50.3150.95240.47377.50.1791.03 x 10-60.6421.51 × 10-61.51 × 10-6896862.40.3280.934Peaches36-902-3259.90.3040.934Plums338.10.143|Potatoes32-1580-7065.70.2881.40 x 10-60.868Raisins327386.20.2171.18 x 10-60.592MeatsBeef, groundBeef, lean674359.30.2351.40 x 10-60.802743768.00.2721.40 x 10-60.844Beef fat9550.50.110729573Beef liver0.2590.8321.18 x 10-61.40 x 10-6Cat food39.771.20.1880.638Chicken breast753265.50.2750.850 Find the freezing time, t, for chicken at an initial temperature of 0 °C, to reach -4 °C at theblasting air temperature, Ta, of -40 °C by using Figure 17-30 of the textbook, and estimate theBiot number using the following Plank's model:t= [L p (1/4 D/h + 1/16 x D²/k)]/(Tf – Ta)where L- latent heat of freezingp- Density of chickenD– diameter of chicken =15 cmh – heat transfer coefficientk - thermal conductivity of chickenTf- freezing temperature

Given Diameter, d = 15 cm Thermal conductivity, k = 0.478 W/mK Heat transfer coefficient, h…

Find the freezing time, t, for chicken at an initial temperature of 0 °C, to reach -4 °C at the blasting air temperature, Ta, of -40 °C by using Figure 17-30 of the textbook, and estimate the Biot number using the following Plank’s model: t= [Lp (1/4 D/h + 1/16 x D²/k)]/(Tf– T.) where L- latent heat of freezing p- Density of chicken D- diameter of chicken = 15 cm h– heat transfer coefficient k – thermal conductivity of chicken Tf- freezing temperature |

Find the freezing time, t, for chicken at an initial temperature of 0 °C, to reach -4 °C at the blasting air temperature, Ta, of -40 °C by using Figure 17-30 of the textbook, and estimate the Biot number using the following Plank’s model: t= [Lp (1/4 D/h + 1/16 x D²/k)]/(Tf– T.) where L- latent heat of freezing p- Density of chicken D- diameter of chicken = 15 cm h– heat transfer coefficient k – thermal conductivity of chicken Tf- freezing temperature |

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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Question

Specific
Heat, Cp
Water
Thermal
Thermal
Content, Temperature, T Density, p Conductivity, k
Ibm/ft3
Diffusivity, a
ft2/s
Food
%(mass)
°F
Btu/h-ft.°F
Btu/lbm-R
Fruits/Vegetables
Apple juice
Apples
Apples, dried
Apricots, dried
Bananas, fresh
1.51 x 10-6
1.47 x 10-6
87
68
62.4
0.323
0.922
85
32-86
52.4
0.242
0.910
41.6
73
53.4
0.127
1.03 x 10-6
0.650
1.22 x 10-6
1.51 × 10-6
43.6
73
82.4
0.217
0.662
76
41
61.2
0.278
0.856
Broccoli
21
35.0
0.223
|
1.42 x 10-6
Cherries, fresh
Figs
Grape juice
92
32-86
65.5
0.315
0.952
40.4
73
77.5
0.179
1.03 x 10-6
0.642
1.51 × 10-6
1.51 × 10-6
89
68
62.4
0.328
0.934
Peaches
36-90
2-32
59.9
0.304
0.934
Plums
3
38.1
0.143
|
Potatoes
32-158
0-70
65.7
0.288
1.40 x 10-6
0.868
Raisins
32
73
86.2
0.217
1.18 x 10-6
0.592
Meats
Beef, ground
Beef, lean
67
43
59.3
0.235
1.40 x 10-6
0.802
74
37
68.0
0.272
1.40 x 10-6
0.844
Beef fat
95
50.5
0.110
72
95
73
Beef liver
0.259
0.832
1.18 x 10-6
1.40 x 10-6
Cat food
39.7
71.2
0.188
0.638
Chicken breast
75
32
65.5
0.275
0.850

Find the freezing time, t, for chicken at an initial temperature of 0 °C, to reach -4 °C at the
blasting air temperature, Ta, of -40 °C by using Figure 17-30 of the textbook, and estimate the
Biot number using the following Plank's model:
t= [L p (1/4 D/h + 1/16 x D²/k)]/(Tf – Ta)
where L- latent heat of freezing
p- Density of chicken
D– diameter of chicken =15 cm
h – heat transfer coefficient
k - thermal conductivity of chicken
Tf- freezing temperature

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