Find the freezing time, t, for chicken at an initial temperature of 0 °C, to reach -4 °C at the blasting air temperature, Ta, of -40 °C by using Figure 17-30 of the textbook, and estimate the Biot number using the following Plank’s model: t= [Lp (1/4 D/h + 1/16 x D²/k)]/(Tf– T.) where L- latent heat of freezing p- Density of chicken D- diameter of chicken = 15 cm h– heat transfer coefficient k – thermal conductivity of chicken Tf- freezing temperature |

Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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Question
Specific
Heat, Cp
Water
Thermal
Thermal
Content, Temperature, T Density, p Conductivity, k
Ibm/ft3
Diffusivity, a
ft2/s
Food
%(mass)
°F
Btu/h-ft.°F
Btu/lbm-R
Fruits/Vegetables
Apple juice
Apples
Apples, dried
Apricots, dried
Bananas, fresh
1.51 x 10-6
1.47 x 10-6
87
68
62.4
0.323
0.922
85
32-86
52.4
0.242
0.910
41.6
73
53.4
0.127
1.03 x 10-6
0.650
1.22 x 10-6
1.51 × 10-6
43.6
73
82.4
0.217
0.662
76
41
61.2
0.278
0.856
Broccoli
21
35.0
0.223
|
1.42 x 10-6
Cherries, fresh
Figs
Grape juice
92
32-86
65.5
0.315
0.952
40.4
73
77.5
0.179
1.03 x 10-6
0.642
1.51 × 10-6
1.51 × 10-6
89
68
62.4
0.328
0.934
Peaches
36-90
2-32
59.9
0.304
0.934
Plums
3
38.1
0.143
|
Potatoes
32-158
0-70
65.7
0.288
1.40 x 10-6
0.868
Raisins
32
73
86.2
0.217
1.18 x 10-6
0.592
Meats
Beef, ground
Beef, lean
67
43
59.3
0.235
1.40 x 10-6
0.802
74
37
68.0
0.272
1.40 x 10-6
0.844
Beef fat
95
50.5
0.110
72
95
73
Beef liver
0.259
0.832
1.18 x 10-6
1.40 x 10-6
Cat food
39.7
71.2
0.188
0.638
Chicken breast
75
32
65.5
0.275
0.850
Transcribed Image Text:Specific Heat, Cp Water Thermal Thermal Content, Temperature, T Density, p Conductivity, k Ibm/ft3 Diffusivity, a ft2/s Food %(mass) °F Btu/h-ft.°F Btu/lbm-R Fruits/Vegetables Apple juice Apples Apples, dried Apricots, dried Bananas, fresh 1.51 x 10-6 1.47 x 10-6 87 68 62.4 0.323 0.922 85 32-86 52.4 0.242 0.910 41.6 73 53.4 0.127 1.03 x 10-6 0.650 1.22 x 10-6 1.51 × 10-6 43.6 73 82.4 0.217 0.662 76 41 61.2 0.278 0.856 Broccoli 21 35.0 0.223 | 1.42 x 10-6 Cherries, fresh Figs Grape juice 92 32-86 65.5 0.315 0.952 40.4 73 77.5 0.179 1.03 x 10-6 0.642 1.51 × 10-6 1.51 × 10-6 89 68 62.4 0.328 0.934 Peaches 36-90 2-32 59.9 0.304 0.934 Plums 3 38.1 0.143 | Potatoes 32-158 0-70 65.7 0.288 1.40 x 10-6 0.868 Raisins 32 73 86.2 0.217 1.18 x 10-6 0.592 Meats Beef, ground Beef, lean 67 43 59.3 0.235 1.40 x 10-6 0.802 74 37 68.0 0.272 1.40 x 10-6 0.844 Beef fat 95 50.5 0.110 72 95 73 Beef liver 0.259 0.832 1.18 x 10-6 1.40 x 10-6 Cat food 39.7 71.2 0.188 0.638 Chicken breast 75 32 65.5 0.275 0.850
Find the freezing time, t, for chicken at an initial temperature of 0 °C, to reach -4 °C at the
blasting air temperature, Ta, of -40 °C by using Figure 17-30 of the textbook, and estimate the
Biot number using the following Plank's model:
t= [L p (1/4 D/h + 1/16 x D²/k)]/(Tf – Ta)
where L- latent heat of freezing
p- Density of chicken
D– diameter of chicken =15 cm
h – heat transfer coefficient
k - thermal conductivity of chicken
Tf- freezing temperature
Transcribed Image Text:Find the freezing time, t, for chicken at an initial temperature of 0 °C, to reach -4 °C at the blasting air temperature, Ta, of -40 °C by using Figure 17-30 of the textbook, and estimate the Biot number using the following Plank's model: t= [L p (1/4 D/h + 1/16 x D²/k)]/(Tf – Ta) where L- latent heat of freezing p- Density of chicken D– diameter of chicken =15 cm h – heat transfer coefficient k - thermal conductivity of chicken Tf- freezing temperature
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