Find the following integrals, showing all working. (a) [2x² (x³ + 5)³/² dx (b) / (c) 4 (d) [* 5x x²-1 dx (4e-2 + t³) dt e3√√-2 2√√√ dx

Evaluate the integral (2x + 5) (x² + 5x + 9) ³dx 3 by making the substitution u = x+5x+9. + C NOTE: Your answer should be in terms of x and not u.

4

Write the integral as the sum of the integral of an odd function and the integral of an even function. Use this simplification to evaluate the integral.

6. Complete the square to get an equivalent expression: 7-6x – x² | No integration necessary on this one!

Why do we use long division? Can I not split the denominator into (x+3)(X-3)?