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(2+1) 2x + 5 (2x + 5)(2x) - (x² − 1)2 (x²-1)² - X 4x² +10x-2x² +2 2 (x²-1)² Dx || 2x² + 10x + 2 (x²-1)² hoose the correct answer below. A. In the first step, the numerator should be (x² - 1) (2x + 5) - (2x)2. B. In the first step, the numerator should be (x² − 1)2-(2x + 5)(2x). Oc. In all three steps, the denominator should be (2x + 5)². D. In the last step, the numerator should be 2x² - 10x + 2.

(2+1) 2x + 5 (2x + 5)(2x) - (x² − 1)2 (x²-1)² - X 4x² +10x-2x² +2 2 (x²-1)² Dx || 2x² + 10x + 2 (x²-1)² hoose the correct answer below. A. In the first step, the numerator should be (x² - 1) (2x + 5) - (2x)2. B. In the first step, the numerator should be (x² − 1)2-(2x + 5)(2x). Oc. In all three steps, the denominator should be (2x + 5)². D. In the last step, the numerator should be 2x² - 10x + 2.

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Find the error in the following work:

Dx 2x + 5 (2x + 5)(2x) - (x²-1)2 (3+5) 2 X 1 - = 2 (x²-1)² 2 4x² + 10x - 2x² + 2 (x²-1)² 2x² + 10x + 2 (x²-1)² Choose the correct answer below. OA. In the first step, the numerator should be (x² - 1) (2x + 5) – (2x)2. B. In the first step, the numerator should be (x² − 1)2 - (2x + 5)(2x). - C. In all three steps, the denominator should be (2x + 5)². OD. In the last step, the numerator should be 2x² - 10x + 2.
Transcribed Image Text:Dx 2x + 5 (2x + 5)(2x) - (x²-1)2 (3+5) 2 X 1 - = 2 (x²-1)² 2 4x² + 10x - 2x² + 2 (x²-1)² 2x² + 10x + 2 (x²-1)² Choose the correct answer below. OA. In the first step, the numerator should be (x² - 1) (2x + 5) – (2x)2. B. In the first step, the numerator should be (x² − 1)2 - (2x + 5)(2x). - C. In all three steps, the denominator should be (2x + 5)². OD. In the last step, the numerator should be 2x² - 10x + 2.
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