Find the expected value for the random variable:X1246.Р(X) 0.210.250.110.43E(X) =%3D

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Answered: Find the expected value for the random…

A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

Section: Chapter Questions

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

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X₂ O The expected value of X+Y-E(X+Y) and the variance of X + Y - Var(X+Y) are: O O O 1 2 3 4 1/6 1/6 1/6 1/6 O 5 6 1/6 1/6 E(X+Y) = 6.5 and Var(X+Y) = 5.85 .a E(X+Y) = 7.25 and Var(X+Y) = 5.8333 b E(X+Y) = 7 and Var(X+Y) = 5.8333 .C .d .e
# Consider a random variable X with the expected value of 5 and E (X²) = 40. Calculate the variance of X. 15 i 9
(2.d) We are interested in the function of X defined by Y = g(X) = X². What is CDF of Y in terms of CDF of X? (Note, in %3D the answer box SQRT=Square Root). Referring to Y = g(X) = XWhat is the expected value (2.e) of the function of the random variable, E[Y?
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An unfair die looks like an ordinary six-sided die but the outcomes are not equally likely. The probability distribution of the face value, XX, is as follows: xixi 1 2 3 4 5 6 Total P(X=xi)P(X=xi) 0.15 0.16 0.33 0.2 0.11 0.05 1 The expected value is computed, E[X]=3.11E[X]=3.11. To find the variance and standard deviation the following table was set up: xixi P(X=xi)P(X=xi) (xi−E[X])2(xi-E[X])2 (xi−E[X])2P(X=xi)(xi-E[X])2P(X=xi) 1 0.15 (1−3.11)2=(−2.11)2=4.4521(1-3.11)2=(-2.11)2=4.4521 4.4521⋅0.15=0.66784.4521⋅0.15=0.6678 2 (2−3.11)2=(−1.11)2=1.2321(2-3.11)2=(-1.11)2=1.2321 1.2321⋅0.16=0.19711.2321⋅0.16=0.1971 3 0.33 (3−3.11)2=(−0.11)2=(3-3.11)2=(-0.11)2= 0.0121⋅0.33=0.0040.0121⋅0.33=0.004 4 0.2 (4−3.11)2=(0.89)2=0.7921(4-3.11)2=(0.89)2=0.7921 0.7921⋅0.2=0.7921⋅0.2= 5 (5−3.11)2=(1.89)2=3.5721(5-3.11)2=(1.89)2=3.5721 3.5721⋅0.11=0.39293.5721⋅0.11=0.3929 6 0.05 8.3521⋅0.05=0.41768.3521⋅0.05=0.4176 E[X]=3.11E[X]=3.11 Total:…
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Find the expected value for the random variable: X 1 2 4 P(X) 0.21 0.25 0.11 0.43 E(X) =