Find the equation of the line that is perpendicular to y = ('/3) x + 2 and goes through (3,-4). a) y = (/3) x + 4 b) y = 3x –13 c) y = 3x + 13 d) у%3D() х — 4 e) y = 3x + 4 %3D %3D | %3D
Find the equation of the line that is perpendicular to y = ('/3) x + 2 and goes through (3,-4). a) y = (/3) x + 4 b) y = 3x –13 c) y = 3x + 13 d) у%3D() х — 4 e) y = 3x + 4 %3D %3D | %3D
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter11: Topics From Analytic Geometry
Section11.3: Hyperbolas
Problem 44E
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Find the equation of the line that is
perpendicular to y = ('/3) x + 2 and
goes through (3,-4).
a) y = ('/3) x + 4
b) у%3D 3х —13
c) y = 3x + 13
d) y = ('/3) x – 4
e) у%3 Зх + 4
%3D
%3D
A
В
C
D
E
MBA Class of 2020 Earns Record
Starting Salaries
SPONSORED BY GEORGETOWN MCDONOUGH](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fb70236e8-1b3e-4da3-8949-665523c3d502%2F5b6e6a67-56ea-423e-8d4b-109ace1521c8%2Ft2u9xp6_processed.jpeg&w=3840&q=75)
Transcribed Image Text:ull TEW LTE
12:37 AM
@ 25% I
proprofs.com
ONLINE PRACTICE TESTS
8%
2/ 25
>
>>
Find the equation of the line that is
perpendicular to y = ('/3) x + 2 and
goes through (3,-4).
a) y = ('/3) x + 4
b) у%3D 3х —13
c) y = 3x + 13
d) y = ('/3) x – 4
e) у%3 Зх + 4
%3D
%3D
A
В
C
D
E
MBA Class of 2020 Earns Record
Starting Salaries
SPONSORED BY GEORGETOWN MCDONOUGH
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