Find the equation of the circle tangent to the line 3x – 4y + 6 = 0 at (2, 3) and passing through (-1, 2). O (z – 1)? + (y – 7)² = 25 %3D O (z + 1)? + (y – 7)² = 25 %3D O z? + y – 2x - 14y+ 20 = 0 2? + y? – 2x - 14y+ 25 = 0

Q: c) Find i. y' for x4 + y = 17 If x = 3 and y = 3, calculate y'

A: Here is the solution of above problem.

Q: (2rz - yz)dr + (2yz – zr)dy – (² – xy + y²)dz = 0.

A: Given that, 2xz-yzdx+2yz-zxdy-x2-xy+y2dz=0

Q: d?y =6- 9x and which passes through the points (0, – 1) and (2, 3) - Find the equation of the curve…

A:

Q: A3) Find the equation of the line tangent to the graph of f(x) = 4x³ + 3x? – 2x – 8 at x = -2.

A:

Q: 1. (D³ - 3D²D + 3)y = 0

A: To Solve: (D3-3D2-D+3)y=0.

Q: 16. (D² + 3D)y = -18x; y = 0, Dy = 0 when x = 0

A: Given differnetial equation ( D2 + 3D )y = -18x

Q: dy Find dx-1 = (5; - x*)() x+1 y =

A: y=5x5-x4x+1x-1

Q: The equation (x - 3y)dy = (2y + 4)dx is exact.

A:

Q: Evaluate xy dx + (x+ y)dy along the.curve y = 4x from (- 3,36) to (- 2,16). C xy dx + (x + y)dy =] C…

A:

Q: . Find P.S. of (16x +5y) dx + (3x+y) dy = 0 of the curre to pass thru the point (1,-3) 2. Find P.S.…

A:

Q: 2. Find P.S. of when y (2x²-xy +y ²) dx − x²(2x-1) dy o y = 1/2. X = /

A:

Q: „ 2x2-5x if y= dx dy Find 5x3 +5

A: y = ( 2x2 - 5x ) / ( 5x3 + 5 ) y'=?

Q: (D²-3D-2)y = 0 Find y when x = In 2 when x=0, y'= 9, Y=0, y=0 4.

A:

Q: Equation xdy + ydx = 0 y"-3y" + 3y + y = 0 (y)¹/² = √/(1+y")4 Order Degree Kind IV DV

A:

Q: If xy + 5ev = 5e, find the value of y" at the point where x = 0. y" =

A:

Q: dy_ sec²y 1- 1+x² 2 when x=0 O y=

A:

Q: 2 dy 67 +13

A:

Q: - y=(x² +3x+1)*

A: on doing differentiation with respect to x

Q: 7. (D³ — 2D² − 5D + 6)y = 0; y = 1, Dy = −7, D²y = 1 when x = 0

A: The given equation is;  (D3-2D2-5D+6)y=0, y=1, Dy=-7, D2y=1 when x=0.

Q: Evaluate (2x - y) dx + (x + 3y) dy. C: x-axis from (0, 0) to (0, -3) and (0, -3) to (8, -3)

A:

Q: d?y -=6-9x dx2 Find the equation of the curve for which and which passes through the points (0, -1)…

A: We will do this question by checking the conditions for the given options.

Q: у4у? -16у +19 dy (y-2)°

A: This indefinite integral can be solved by the substitution method.

Q: 1. (D2 – 2D + 5)y = 0

A:

Q: 4. (3x – y)2 = 6x + 2y + 23 @ (1,-2) 5. x(x² – y²) = 3 @ (-1,2)

A: 4) (3x-y)2=6x+2y+23, @(1,-2) 5)x(x2-y2)=3, @(-1,2).

Q: Evaluate / (2x - y) dx + (x + 5y) dy. C: x-axis from (0, 0) to (0, -5) and (0, -5) to (7, -5)

A: