Find the equation in standard form of the following hyperbola. Select the correct answer below: 2 (x - 3)² (y+3)² 25 (x + 3)²- - (y-3)² 25 2 (y+3)² 25 (x+3)² (y+3)² 25 (y+3)² 25 - - (x - 3)² = 1 = 1 ² = 1 (y-3)² = 1 25 - (x + 3)² = 1 - (x + 3)² = 1 25x² + 150x - y² + 6y + 191 = 0

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Q: Find the equation of the hyperbola with vertices (-7,3) and (1, 3) and foci (-11, 3) and (5,3).…

A: Vertices   -7,3 and     (1,3)Foci                -11,3     and   5,3

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A: To find the standard form of the equation of the parabola with the below characteristics. Vertex:…

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Q: The parabola described in the equation y = 2(x - 4)2 + 3 has the directrix at y = -1. The focus of…

A: As per the guidelines we are supposed to solve one question at a time. Please repost other questions…

Q: Write an equation in standard form for a hyperbola with center at (4, 0), vertex (10, 0), and focus…

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Q: Arrange the parabolas represented by the equations according to the positions of their foci on the…

A: The standard form of a parabola is  (x – h)2 = a(y – k) where (h, k) is the vertex.

Q: Graph the hyperbola (y+3)2/16-(x+6)2/4=1

A: The given equation is (y+3)2/16-(x+6)2/4=1.