Write an equation in standard form for a hyperbola with center at (4, 0), vertex (10, 0), and focus (12, 0). Graph

Q: 31) Center: (1, -2) Vertex: (1, -7) Focus: (1, 2)

A: I have solved step by step in detail ..go through the solution

Q: For the ellipse equation: 4x^2 + 9y^2 = 36 find the center, vertices, foci and graph it.

A: The given equation of ellipse is:4x2+9y2=36x29+y24=1

Q: Determine the directrix and axis of symmetry of a parabola with vertex (4,-2) and focus (4,4)

A: The distance between the vertex and the focus is same as the distance between the vertex and the…

Q: Graph the equation. Identify the focus and directrix of the parabola. y² =

A: y2=−4xcompare with y2=−4ax

Q: How do I write an equation for a hyperbola that looks like this?

A: Hyperbola equation..

Q: Graph the hyperbola 16x^2−32x−4y^2−24y−84=0, noting the center, vertices, cover-tices, and foci.

A: The given equation of hyperbola is 16x2-32x-4y2-24y-84=0. Convert the equation of hyperbola into its…

Q: -16 + -12 -8 -4 20 94 16- 12+ 8 4 -8- + -12+ -16+ 4 8 12 + + 16 20

A: y2=7x

Q: Find the focus and directrix of the parabola with the equation 6y^2+10x=0. Then choose the correct…

A: Given that, the equation of the parabola is 6y2+10x=0 6y2+10x=06y2=-10xy2=-10x6y2=-4512x Compare the…

Q: Can you do a parabola with the starting point being (0,0)

A: Given a parabola with equation y=x2

Q: Locate the vertex, focus, directrix and axis of symmetry of the parabola y^2-5x+12y=-16.

A:

Q: how do you graph a parabola

A:

Q: Write an equation of the ellipse in standard form ((x-h)/a)^2 + ((y-k)/b)^2 =1

A: Standard form of ellipse isx-h2a2+y-k2b2=1

Q: derive the standard form of equation for a hyperbola?

A: A cartesian coordinate system contains two mutually perpendicular number lines named x axis and y…

Q: Write the equation of the hyperbola 25x^2-9y^2-150x-36y-36=0 in standard form.

A:

Q: Find the equation of an ellipse whose foci belong to the x-axis and passes through the points (4,3)…

A: