Find the energy of r(t) = 1 0 2te- p (¹), where p(t) is the pulse -5 -4 -3 -2 -1 0 t 1 2 3 4 5

Introductory Circuit Analysis (13th Edition)
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ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
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**Problem Statement:**

Find the energy of \( x(t) = 2te^{-\frac{t}{2}} p\left(\frac{t+1}{3}\right) \), where \( p(t) \) is the pulse.

**Graph Explanation:**

The graph represents a pulse function \( p(t) \) on a Cartesian plane. The vertical axis represents the amplitude of the pulse, and the horizontal axis represents time \( t \).

- The amplitude oscillates between 0 and 1.
- The pulse is centered around \( t = -1 \) with a width spanning from \( t = -3 \) to \( t = 3 \).
- The pulse maintains an amplitude of 1 between \( t = -1 \) and \( t = 1 \).
- Outside this interval, the amplitude is 0, indicating that the pulse is active only in this range.

This pulse function is used in the expression for \( x(t) \) to determine the energy of the signal.
Transcribed Image Text:**Problem Statement:** Find the energy of \( x(t) = 2te^{-\frac{t}{2}} p\left(\frac{t+1}{3}\right) \), where \( p(t) \) is the pulse. **Graph Explanation:** The graph represents a pulse function \( p(t) \) on a Cartesian plane. The vertical axis represents the amplitude of the pulse, and the horizontal axis represents time \( t \). - The amplitude oscillates between 0 and 1. - The pulse is centered around \( t = -1 \) with a width spanning from \( t = -3 \) to \( t = 3 \). - The pulse maintains an amplitude of 1 between \( t = -1 \) and \( t = 1 \). - Outside this interval, the amplitude is 0, indicating that the pulse is active only in this range. This pulse function is used in the expression for \( x(t) \) to determine the energy of the signal.
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