Find the emfs 1 and 2 in the circuit shown in the figure and find the potential difference of point b relative to point a. 1.00 20.0 V ww 4.00 Ω a ww 2.00 A 1.00 2 &₂ ww 1.00 A 6.00 Ω 1.000 Ε wwob 2.00 Ω www

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A: Position given = 2.6i^  - 6.2j^ +2.2k^ V (Potential) = 1.5xyz2 E = -(gradient of V)

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A: Solution:-Given thatnumber of moles (n)=3.28 molideal monatomic gas

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A: C1=2.8uf C2=5.8uf Voltage applied (V)= 430 v

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A: GivenInitial speed u = 47.6 m/sAngle θ =44.2ot = 1.50 s

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Q: Can you address part e here

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Q: Please answer d as well if possible I will really appreciate it!!!! Question in photo

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