FIND THE ELECTRIC POTENTIAL, V, DUE TO A UNIFORMLY DISTRIBUTED CHARGE, ON A RING OF RADIUS, R, AT ANY POINT ON THE VERTICAL AXIS THAT PASSES THROUGH THE CENTRE OF THE RING. USE YOUR ANSWER TO CALCULATE THE ELECTRIC FIELD DUE TO THE CHARGE DISTRIBUTION. ring

FIND THE ELECTRIC POTENTIAL, V, DUE TO A UNIFORMLY DISTRIBUTED CHARGE, ON A RING OF RADIUS, R, AT ANY POINT ON THE VERTICAL AXIS THAT PASSES THROUGH THE CENTRE OF THE RING. USE YOUR ANSWER TO CALCULATE THE ELECTRIC FIELD DUE TO THE CHARGE DISTRIBUTION. ring

Physics for Scientists and Engineers: Foundations and Connections

1st Edition

ISBN:9781133939146

Author:Katz, Debora M.

Publisher:Katz, Debora M.

Chapter25: Gauss’s Law

Section: Chapter Questions

Problem 58PQ: A charged rod is placed in the center along the axis of a neutral metal cylinder (Fig. P25.57). The...

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Calculate the electric field due to a uniformly charged rod of length L, aligned with the x-axis with one end at the origin; at a point P on the z-axis.
A thin conducing plate 2.0 m on a side is given a total charge of 10.0C . (a) What is the electric field 1.0 cm above the plate? (b) What is the force on an electron at this point? (c) Repeat these calculations for a point 2.0 cm above the plate. (d) When the electron moves from 1.0 to 2.0 cm above the plate, how much work is done on it by the electric field?
(a) What is the electric field 5.00 m from die center of the terminal of a Van de Graaff with a 3.00-mC charge, noting that the field is equivalent to that of a point charge at the center of the terminal? (b) At this distance, what force does the field exert on a 2.00C charge on the Van de Graaff’s belt?
A When we find the electric field due to a continuous charge distribution, we imagine slicing that source up into small pieces, finding the electric field produced by the pieces, and then integrating to find the electric field. Lets see what happens if we break a finite rod up into a small number of finite particles. Figure P24.77 shows a rod of length 2 carrying a uniform charge Q modeled as two particles of charge Q/2. The particles are at the ends of the rod. Find an expression for the electric field at point A located a distance above the midpoint of the rod using each of two methods: a. modeling the rod with just two particles and b. using the exact expression E=kQy12+y2 c. Compare your results to the exact expression for the rod by finding the ratio of the approximate expression to the exact expression. FIGURE P24.77 Problems 77 and 78.
A Two positively charged spheres with charges 4e and e are separated by a distance L and held motionless. A third charged sphere with charge Q is set between the two spheres and along the line joining them. The third sphere is in static equilibrium. What is the distance between the third charged sphere and the sphere that has charge 4e?
The electric field at a point on the perpendicular bisector of a charged rod was calculated as the first example of a continuous charge distribution, resulting in Equation 24.15:E=kQy12+y2j a. Find an expression for the electric field when the rod is infinitely long. b. An infinitely long rod with uniform linear charge density also contains an infinite amount of charge. Explain why this still produces an electric field near the rod that is finite.
A charged rod is placed in the center along the axis of a neutral metal cylinder (Fig. P25.57). The rod has positive charge uniformly distributed. (Ignore the ends.) a. Find expressions for the electric fields in all regions: r a, a r b, b r c, and r c. b. Plot your expressions on one graph. Is the electric field continuous or discontinuous? Explain.
An electron and a proton, each starting from rest, are accelerated by the same uniform electric field of 200 N/C. Determine the distance and time for each particle to acquire a kinetic energy of 3.21016 J.
Consider a ring of radius R with the total charge Q spread uniformly over its perimeter. What is the potential difference between the point at the center of the ring and a point on its axis a distance 2R from the center?
Give a plausible argument as to why the electric field outside an infinite charged sheet is constant.
A very long line of charge with a linear charge density, , is parallel to another very long line of charge with a linear charge density, 2. Both lines are parallel to the y-axis, and are the same distance r from the y-axis, where the first wire is to the left of the origin and the second is to the right. Use Gausss law and the principle of superposition to find an expression for the magnitude of the electric field at the origin.
Figure P24.17 shows a dipole (not drawn to scale). If the positive particle has a charge of 35.7 mC and the particles are 2.56 mm apart, what is the (approximate) electric field at point A located 2.00 m above the dipoles midpoint?