Answered: Find the electric flux (in units of…

Find the electric flux (in units of N.m2/C) through the surface of the rectangle ( 30 cm x 40 cm) in the figure given that E = 443.5 N/C. Ner

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

See similar textbooks

Related questions

Q: Consider a closed triangular box resting within a horizontal electric field of magnitude E = 6.66 x…

A: E=6.66x104NC Using figure: L=30cm=0.30mh=10cm=0.10mθ=60∘

Q: Q39. Electric flux through a surface is maximum when O Angle of inclination between the field and…

A: we know that electric flux through the surface is given by φ = φ = E dA cosθ hence flux will be…

Q: An electric field of 600N/C makes an angle of 20.00 with the surface vector, which has a magnitude…

Q: A uniform electric field of magnitude 2.7 x 10 N/C is perpendicular to a square sheet with sides 2.5…

A: Magnitude of electric field, E = 2.7 × 10⁴ N/C Length, L = 2.5 m We know, The area will be: A = L²…

Q: What is the area of a rectangle whose electric flux is 38 C2/Nm2 and electric field of 79 nN/C

A: The electric flux is given by ϕ = E A cosθ where, E is the electric field, A is the area, and θ is…

Q: A flat circle of radius 31.25 cm is rotated through a uniform horizontal electric field of 7.5 N/C.…

A: The expression for the electric flux is written as, Here, E, A and θ represent the electric field,…

Q: A cylinder of radius 0.5 m and height 3 m is placed on a system of reference so one of its bases on…

A: We will answer this question by using expression for Electric flux and Gauss's law. The details are…

Q: 10. A flat sheet is in the shape of a rectangle with sides of lengths 0.450 m and 0.675 m. The sheet…

Q: Find the electric flux through the plane surface shown in the figure below if = 61.8°, E = 372 N/C,…

A: We have a plane square surface of side d=4.7 cm=0.047 m through which an electric field of magnitude…

Q: Find the electric flux ( in units of N.m /C) through the surface of the rectangle ( 30 cm x 40 cm)…

A: Given : Area (A) = 30 cm x 40 cm = 1200 cm = 0.12 m2 E = 386.3 N/C θ = 30°

Q: f we assume that there is an electric field in the form of E=2z(k), which of the following gives the…

A: The net charge enclosed by the cube is 2a³ε₀ Explanation : Given, E = 2z k Since the electric field…

Q: A closed surface is in the form of a block with length c, width b and height a. In this room there…

A: The objective of the question is to find the total electric flux over the closed surface and the…

Q: An electric field of 5.4 N/C passes through an area of 3.4 cm2. Calculate the flux in units of 10^-4…

A: Given data: Electric field (E) = 5.4 N/C Area (A) = 3.4 cm2 = 3.4×10-4 m2 Angle between electric…

Q: An electric field E = (1+ 2x)N/Cî passes through a cube of side a = 1m as shown in the figure. Find…

Q: a. Calculate the net enclosed charge by the Gaussian surface of radius r=20m. b. Electric field at…

A: Since we only answer up to 3 sub-parts, we’ll answer the first 3. Please resubmit the question and…

Q: The surface shown is a square and has a side length of 11.0 cm. The electric field acting on this…

A: It is given that

Q: When a piece of paper is held with one face perpendicular to a uniform electric field the flux…

A: Recall ϕ=electric flux=EAcosθ θ is angle between electric field and area vector.

Q: Find the electric flux (in units of N.m2/C) through the surface in the figure ( dashed line) given…

Q: A rectangular surface extends from x = 0 to x = 50.0 cm and from y = 0 to y = 42.0 cm in the xy…

Q: A closed surface is in the form of a block with length c, width b and height a. In this room there…

A: The objective of the question is to find the total electric flux over the closed surface and the…

Q: A point charge produces an electric flux of +305 N-m2 /C through a gaussian sphere of radius 14.5 cm…

Q: IS a ge. Wld ough the sur the spner units of N m2/C? Select one: O a. 1.75 x105 O b. 1.7x 10-16 O .…

A: Use Gauss's Law to find flux Flux=sum of all charges within the surfaceε0 value of ε0=8.85×10-12…

Q: A 3.0 cm diameter circle lies in yz -plane with unit area vector pointing in x-direction. What is…

Q: Find the electric flux ( in units of N.m2/C) through the surface of the rectangle ( 30 cm × 40 cm)…

Q: A 32.0-cm-diameter circular loop is rotated in a uniform electric field until the position of…

A: Data provided:Diameter (d) = 32.0 cm = 0.320 mMaximum electric flux (Φ) = 5.8×105…

Q: -30 +3Q +5Q +2Q -7Q Select one: A. -52.74 B. 73.84 C. 0.00 D. 52.74 E. -73.84

Q: A 3.60 cm x 4.10 cm rectangle lies in the xy-plane. ▼ ▼ Part A What is the electric flux through the…

Q: A 30.0-cm-diameter circular loop is rotated in a uniform electric field until the position of…

Q: A constant electric field 5.8 N/C is pointing in the positive x-direction. Calculate the magnitude…

Q: Find the electric flux ( in units of N.m2/C) through the surface of the rectangle ( 30 cm x 40 cm)…

Q: A uniform electric feild that has magnitude E is applied parallel to the axis of a hollow half a…

A: Given: The strength of the electric field is E. The radius of the spehre is r.

Q: A vertical electric field of magnitude 2.20 x 104 N/C exists above the Earth's surface on a day when…

Q: A electric field at 3.2 cm from the centre of a long copper rod of radius 0.6 cm has a magnitude 6.6…

A: Given value--- Electric field = 6.6 N/C. radius = 0.6 cm. We have to find--- What is the charge…

Q: Find the electric flux (in units of N.m-/C) through the surface of the rectangle (30 cm x 40 cm) in…

Q: Find the electric flux ( in units of N.m2/C) through the surface of the rectangle ( 30 cm × 40 cm)…

Q: Find the electric flux ( in units of N.m2/C) through the surface of the rectangle ( 30 cm x 40 cm)…

A: We know that the Electric flux(∅) through surface of rectangle having area(A) and Electric field(E)…

Q: Find the electric flux ( in units of N.m2/C) through the surface of the rectangle ( 30 cm x 40 cm)…

A: Given- Electric field E=277.9 N/CArea A=30 cm×40 cm=.3×.4=0.12 m2

Q: A flat surface of area 3.80 m2 is rotated in a uniform electric field of magnitude E = 6.80 x 10…

A: Given data : Area = 3.80 m2 Electric field = 6.80×105N/C

Q: A Gaussian surface has the form of a cube. If 4 nC of charge is placed inside the cube and 3 nC of…

Q: Find the electric flux (in units of N.m /C) through the surface of the rectangle (30 cm x 40 cm) in…

Q: Find the electric flux ( in units of N.m2/C) through the surface of the rectangle ( 30 cm X 40 cm)…

Q: A 39.0-cm-diameter circular loop is rotated in a uniform electric field until the position of…

A: We are given a circular loop. We are given its diameter. We are given magnitude of flux when flux is…

Concept explainers

Electric Charges and Fields

One of the fundamental properties is the electromagnetic property. Charge cannot be destroyed by any process and this contributes formally to the law of charge conservation.

Question

Find the electric flux ( in units of N.m2/C) through the surface of the rectangle ( 30 cm x 40 cm) in the figure given that E = 443.5 N/C.
Normal
E
0 30
Select one:
O A. 26.61
OB. 16.19
OC. 53.22
OD. 46.09
O E. 62.09
Next page

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

This is a popular solution!

SEE SOLUTION Check out a sample Q&A here

Step 1

VIEW

Step 2

VIEW

Trending now

This is a popular solution!

Step by step

Solved in 2 steps

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.

Similar questions

P10
A circular surface with a radius of 0.071 m is exposed to a uniform electric field of magnitude 1.47 x 104 N/C. The electric flux through the surface is 64 N-m2/C. What is the angle between the direction of the electric field and the normal to the surface? Number i eTextbook and Media Units
An electric flux of 8.99 x10-12 Nm?/C is passing through a sphere created by 1.25x10-3 N/C electric field. What is the radius of the sphere?
Find the electric flux (in units of N.m2/C) through the surface of the rectangle ( 30 cm x 40 cm) in the figure given that E = 399.7 N/C. Normal E 0-30
Determine the charge density p, due to the electric flux density D = 4p sin o ap+ 2p cos o as + 2z²a. C/m²
9. A 40.0 cm diameter loop is rotated to the position where the greatest flux is obtained in a uniform electric field. At this location, the flux is measured as 5 .20x10 ^ 5 N.m ^ 2 / C. Find the magnitude of the electric field. 8.14x105N / C2.14x106 NC5.44x106 N / C6.14x106N / C4.14x106N / C
A hollow sphere of radius 1.54 m is in a region where the electric field is radial and directed toward the center of the sphere. If the magnitude of the field at the surface of the sphere is 21.6 N/C, what is the net electric flux through the spherical surface? N. m²/c
Find the electric flux through the closed surface whose cross-section is shown below. a a -2.0 × 10-6 C a. -2.00 × 10-N·m²/C O b. -2.00 × 10-6a² N·m²/C -2.25 × 105 N·m²/C c. d. -2.25 × 105a² N·m²/C
A electric field at 3.8 cm from the centre of a long copper rod of radius 0.7 cm has a magnitude 3.6 N/C and is directed outward from the axis of the rod. Part 1 What is the charge per unit length of the copper rod? = number (rtol=0.03, atol=0) C/m Part 2 What would be the electric flux through a cube of side 8.0 cm situated such that the rod passes through the opposite sides of the cube perpendicularly? number (rtol=0.03, atol=0) Nm?/C
An electric field E = (-1.19 x 103 N . m²/C) X What is the direction of the area vector relative to the direction of the electric field vector? What is the magnitude of the field at the surface of the spherical shell under consideration? How is the flux through the spherical shell related to the net charge inside the shell? UC is produced by a certain spherically symmetric charge distribution. Determine the charge inside a spherical shell of radius 25.0 cm due to this charge distribution.
QUESTION 1 A uniformly charged insulating sphere of radius a = 10.0 cm produces an electric field E = 200 N/C at a distance of 7.53 cm from the center. Find the volume charge density p (in nC/m3) of the sphere.
A closed surface is in the form of a block with length c, width b and height a. In this room there is an electric field parallel to the x axis with magnitude: E = A + Bx, where A and B are constants. a. Determine the total flux over the closed surface. b. Determine the amount of charge covered by the payload. N x = a ko-