Find the electric field everywhere of an infinite uniform line charge with total charge Q. Sol. Using Gauss's Law: (contour integral E with rightwards harpoon with barb upwards on top) * (stack d A with rightwards harpoon with barb upwards on top) = ___________ /epsilon0 EA = ___________ / epsilon0 Since, its the line charge we use the area of a cylinder surrounding the line charge E*2pi ___________ L= ___________ / epsilon0 But all the charged get enclosed by the cylinder area, so qenc = Q Deriving, we get: E = (1/2(pi*epsilon0))*(___________ /rL)   **see picture for the symbols used

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Find the electric field everywhere of an infinite uniform line charge with total charge Q.

Sol.

Using Gauss's Law:

(contour integral E with rightwards harpoon with barb upwards on top) * (stack d A with rightwards harpoon with barb upwards on top) = ___________ /epsilon0

EA = ___________ / epsilon0

Since, its the line charge we use the area of a cylinder surrounding the line charge

E*2pi ___________ L= ___________ / epsilon0

But all the charged get enclosed by the cylinder area, so

qenc = Q

Deriving, we get: E = (1/2(pi*epsilon0))*(___________ /rL)

 

**see picture for the symbols used

Find the electric field everywhere of an infinite uniform line charge with total charge Q.
Sol.
Using Gauss's Law:
EA =
Since, its the line charge we use the area of a cylinder surrounding the line charge
E*2T
But all the charged get enclosed by the cylinder area, so
denc -Q
Deriving, we get:
E- (1/2 TEO )*(
IrL)
Transcribed Image Text:Find the electric field everywhere of an infinite uniform line charge with total charge Q. Sol. Using Gauss's Law: EA = Since, its the line charge we use the area of a cylinder surrounding the line charge E*2T But all the charged get enclosed by the cylinder area, so denc -Q Deriving, we get: E- (1/2 TEO )*( IrL)
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