ric Fields due to Point Charges An uneven dipole is located along the x-axis and centered on the origin as drawn. Its positive end has twice as much 2a +1 charge as its negative end. Each charge is located a distance a away from the origin along the x-axis. In terms of k, q, and a, find the electric field vector only at а POINT 1 and POINT 2. Your answers should be simplified 2 numerically until they are in the form: E = (0.123, -2.345), for example. -2a +29 2a
ric Fields due to Point Charges An uneven dipole is located along the x-axis and centered on the origin as drawn. Its positive end has twice as much 2a +1 charge as its negative end. Each charge is located a distance a away from the origin along the x-axis. In terms of k, q, and a, find the electric field vector only at а POINT 1 and POINT 2. Your answers should be simplified 2 numerically until they are in the form: E = (0.123, -2.345), for example. -2a +29 2a
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