ric Fields due to Point Charges An uneven dipole is located along the x-axis and centered on the origin as drawn. Its positive end has twice as much 2a +1 charge as its negative end. Each charge is located a distance a away from the origin along the x-axis. In terms of k, q, and a, find the electric field vector only at а POINT 1 and POINT 2. Your answers should be simplified 2 numerically until they are in the form: E = (0.123, -2.345), for example. -2a +29 2a

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ric Fields due to Point Charges
An uneven dipole is located along the x-axis and centered on
the origin as drawn. Its positive end has twice as much
2a
1
charge as its negative end. Each charge is located a distance
a away from the origin along the x-axis.
In terms of k, q, and a, find the electric field vector only at
а
POINT 1 and POINT 2. Your answers should be simplified
2
numerically until they are in the form:
E = (0.123, -2.345), for example.
-2a +29
2a
Transcribed Image Text:ric Fields due to Point Charges An uneven dipole is located along the x-axis and centered on the origin as drawn. Its positive end has twice as much 2a 1 charge as its negative end. Each charge is located a distance a away from the origin along the x-axis. In terms of k, q, and a, find the electric field vector only at а POINT 1 and POINT 2. Your answers should be simplified 2 numerically until they are in the form: E = (0.123, -2.345), for example. -2a +29 2a
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