Find the domain of the following rational function. x+3 h(x) = x -9 Select the correct choice below and, if necessary, fill in the answer box to complete your choice. O A. The domain of h(x) is {x|x# ). (Type an integer or a fraction. Use a comma to separate answers as needed.) O B. There are no restrictions on the domain of h(x).
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When it comes to the concept of polynomial equations, quadratic equations can be said to be a special case. What does solving a quadratic equation mean? We will understand the quadratics and their types once we are familiar with the polynomial equations and their types.
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![**Rational Functions: Determining the Domain**
When analyzing rational functions, it is important to determine the domain, which includes all possible input values (x-values) for which the function is defined. For the function given, certain values of \(x\) may cause the function to become undefined.
Given Rational Function:
\[ h(x) = \frac{x + 3}{x^2 - 9} \]
**Steps to Determine the Domain:**
1. **Identify the Denominator:**
The denominator of the function is \(x^2 - 9\).
2. **Set the Denominator to Zero:**
To find the values to exclude from the domain, set the denominator equal to zero and solve for \(x\).
\[
x^2 - 9 = 0
\]
\[
(x - 3)(x + 3) = 0
\]
\[
x = 3, \, -3
\]
3. **Exclude these Values from the Domain:**
The function becomes undefined when \(x = 3\) or \(x = -3\), so these values must be excluded from the domain.
**Choices:**
- **A.** The domain of \(h(x)\) is \(\{x | x \neq 3, -3\}\). (Type an integer or a fraction. Use a comma to separate answers as needed.)
- **B.** There are no restrictions on the domain of \(h(x)\).
For this function, the correct choice is **A** because the values \(x = 3\) and \(x = -3\) make the denominator zero, causing the function to be undefined.
**Conclusion:**
When determining the domain of a rational function, always solve for the values that make the denominator zero and exclude them from the domain.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F1668cca6-eb9e-4ed5-b172-e483e25708ae%2Fae8bd9e0-53d3-4636-82fc-5654951cb185%2Fzw9pz3z_processed.jpeg&w=3840&q=75)
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