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- Evaluate along the curve y=x2 from (-1,1) to (2,4). First find the vector valued function r(t) defining the curve.Let R be a differentiable vector-valued function such that R'(t) = (3t2,2tvt? + 1, 2t + 3) and R(1) = (4, *2, 3). Find R(0).Let the velocity vector be v(t)=⟨5t^4,−3sin(t),4exp(2t)⟩ and the initial position vector be r(0)=⟨−1,6,−1⟩. Compute the position vector r(t).