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Find the direction and magnitude of the minimum velocity of charge q = +2e that will produce the magnetic force F shown in the figure below. (Measure the angle counterclockwise from the x axis in the xz plane. Take the magnitudes of F as 2.11  10-11 N and the magnitude of B as 1.83 T.) magnitude   direction

Find the direction and magnitude of the minimum velocity of charge q = +2e that will produce the magnetic force F shown in the figure below. (Measure the angle counterclockwise from the x axis in the xz plane. Take the magnitudes of F as 2.11  10-11 N and the magnitude of B as 1.83 T.) magnitude   direction

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Find the direction and magnitude of the minimum velocity of charge q = +2e that will produce the magnetic force F shown in the figure below. (Measure the angle counterclockwise from the x axis in the xz plane. Take the magnitudes of F as 2.11  10-11 N and the magnitude of B as 1.83 T.)

magnitude  
direction 
B X- 45.0° F
Transcribed Image Text:B X- 45.0° F
Expert Solution
Step 1

Given,

charge of the particle is 

q=+2e=2×1.6×10-19C=3.2×10-19C

the magnitude of the magnetic field is B=1.83T

And the magnetic field is in the y direction.

Then,

B→=1.83j^T

And the magnitude of the force is F=2.11×10-11N

The force is in xz plane and it is 45o from the x-axis.

 

Then the x component of force is 

Fx=Fcos45o=2.11×10-11N×cos45o=1.5×10-11N

the y component of force is 

Fy=0

the z component of force is 

Fz=Fcos45o=2.11×10-11N×sin45o=1.5×10-11N

So force will be

F→=1.5×10-11Ni^+1.5×10-11Nk^=1.5×10-11i^+k^N

Let the velocity of the charged particle is

v→=vxi^+vyj^+vzk^

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