Find the differential gain of the bioamplifier Ad= out Vin · You can assume common mode potential at the input as zero. You can assume VA=+1/2 and VB=-1/2. ji. By assuming the differential input of the amplifier as zero, find the common mode gain AcM=VOUT / VCM of the bioamplifier. iii. Calculate the Common Mode Rejection Ratio (CMRR) of the bioamplifier in dB. If you record an ECG signal with this amplifier, you observe there is a small powerline interference on the VoUT due to displacement current. The EKG amplitude at the output is 2V and the amplitude of the powerline at the output is 9mV. Then what are iv.

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There are 2 different solutions, but they are both different, can you solve them again more carefully?

1.
A differential bioamplifier is shown below.
VA
10kO
101KQ
101kQ
+
VIN
1kQ
VουT
www
VBo
10kN
Find the differential gain of the bioamplifier Ad= Vout/
Vin · You can assume common mode potential at the input as zero.
i.
You can assume VA=+1/2 and VB=-1/2.
By assuming the differential input of the amplifier as zero,
find the common mode gain ACM=VOUT/ VCM of the bioamplifier.
ii.
iii.
Calculate the Common Mode Rejection Ratio (CMRR) of
the bioamplifier in dB.
iv.
If you record an ECG signal with this amplifier, you
observe there is a small powerline interference on the VOUT due to
displacement current. The EKG amplitude at the output is 2V and
the amplitude of the powerline at the output is 9mV. Then what are
the actual common voltage and the EKG signal amplitudes
recorded on the electrodes?
Transcribed Image Text:1. A differential bioamplifier is shown below. VA 10kO 101KQ 101kQ + VIN 1kQ VουT www VBo 10kN Find the differential gain of the bioamplifier Ad= Vout/ Vin · You can assume common mode potential at the input as zero. i. You can assume VA=+1/2 and VB=-1/2. By assuming the differential input of the amplifier as zero, find the common mode gain ACM=VOUT/ VCM of the bioamplifier. ii. iii. Calculate the Common Mode Rejection Ratio (CMRR) of the bioamplifier in dB. iv. If you record an ECG signal with this amplifier, you observe there is a small powerline interference on the VOUT due to displacement current. The EKG amplitude at the output is 2V and the amplitude of the powerline at the output is 9mV. Then what are the actual common voltage and the EKG signal amplitudes recorded on the electrodes?
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