Find the differential equation of the following function (x – 3y + 2)dx + 3(x + 3y – 4)dy = 0 x-1 a. In[(x – 1)² – 9(y – 1)²] – Arctan 3 (у-1) x-1 b. In[(x — 1)2 + 9(у — 1)?]— Arctan = C (y-1) x-1 c. In[(x – 1)2 + 9(y – 1)²] – Arctan = C 3(y-1) d. In[(x – 1)² + 9(y – 1)²] – Arctan - 3(х-1) y-1 e. None of the above
Find the differential equation of the following function (x – 3y + 2)dx + 3(x + 3y – 4)dy = 0 x-1 a. In[(x – 1)² – 9(y – 1)²] – Arctan 3 (у-1) x-1 b. In[(x — 1)2 + 9(у — 1)?]— Arctan = C (y-1) x-1 c. In[(x – 1)2 + 9(y – 1)²] – Arctan = C 3(y-1) d. In[(x – 1)² + 9(y – 1)²] – Arctan - 3(х-1) y-1 e. None of the above
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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