Solve (x² 1 + 2y) dx + (1 - x²) dy = 0; when x = 2, y = 1 1) (x + 1 + 2 ln x 1|) b. (x + 1) y = (x − 1) (x − 1 + 2 ln|x − 1|) c. (x 1) y = (x + 1) (x +1+2ln|x − 1|) a. (x + 1) y = (x Your answer is correct. The correct answer is: -
Solve (x² 1 + 2y) dx + (1 - x²) dy = 0; when x = 2, y = 1 1) (x + 1 + 2 ln x 1|) b. (x + 1) y = (x − 1) (x − 1 + 2 ln|x − 1|) c. (x 1) y = (x + 1) (x +1+2ln|x − 1|) a. (x + 1) y = (x Your answer is correct. The correct answer is: -
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter5: Inverse, Exponential, And Logarithmic Functions
Section: Chapter Questions
Problem 18T
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