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Find the derivative. 5) y -2. 9 sec x A) y'- 9 wec x tan x B) y'-9 tan?x C)y'--9 D) y' =-9 sec x tan x 9 cse 6) y = (cse x + cot x)(csc x - cot x) A) y'=0 C) y'=- csC x cot x B) y' = 1 D) y'=- csc² x

Find the derivative. 5) y -2. 9 sec x A) y'- 9 wec x tan x B) y'-9 tan?x C)y'--9 D) y' =-9 sec x tan x 9 cse 6) y = (cse x + cot x)(csc x - cot x) A) y'=0 C) y'=- csC x cot x B) y' = 1 D) y'=- csc² x

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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7) s = 5 - csc t + 14 ds A) 54. dt B) 뜻-4-cot2t + 14 - csc t cot t %3! ds 54 + csc t cot t dt ds D) -514 + cot2t dt
Transcribed Image Text:7) s = 5 - csc t + 14 ds A) 54. dt B) 뜻-4-cot2t + 14 - csc t cot t %3! ds 54 + csc t cot t dt ds D) -514 + cot2t dt
Find the derivative. 5) y=2.9 sec x A)y B) y'-.9 tan²x 9 sec x tan x C) y'=--9 csc x D) y'=-+9 sec x tan x 6) y = (csc x + cot x)(csc x - cot x) A) y'=0 B) y'=1 D) y'=- csc2x C) y'=- csc x cot x
Transcribed Image Text:Find the derivative. 5) y=2.9 sec x A)y B) y'-.9 tan²x 9 sec x tan x C) y'=--9 csc x D) y'=-+9 sec x tan x 6) y = (csc x + cot x)(csc x - cot x) A) y'=0 B) y'=1 D) y'=- csc2x C) y'=- csc x cot x
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