Find the current passed through 5 ohm resistor from from point v1 to v2 that come from each current source * 1Ω 4Ω V3 ww V4 1 A 5Ω V2 3А 10 2 2 A O 1(1A) =-1A I(2A) =-2A I(3A) =3A None of the mentioned |(1A) =-1A I(2A) =-2A I(3A) =1.3A O I(1A) =-1A I(2A) =-2A I(3A) =0A O I(1A) =1A 1(2A) =2A I(3A) =3A O I(1A) =-1A I(2A) =-2A I(3A) =1A O I(1A) =1A I(2A) =2A I(3A) =0A
Find the current passed through 5 ohm resistor from from point v1 to v2 that come from each current source * 1Ω 4Ω V3 ww V4 1 A 5Ω V2 3А 10 2 2 A O 1(1A) =-1A I(2A) =-2A I(3A) =3A None of the mentioned |(1A) =-1A I(2A) =-2A I(3A) =1.3A O I(1A) =-1A I(2A) =-2A I(3A) =0A O I(1A) =1A 1(2A) =2A I(3A) =3A O I(1A) =-1A I(2A) =-2A I(3A) =1A O I(1A) =1A I(2A) =2A I(3A) =0A
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
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KVL and KCL
KVL stands for Kirchhoff voltage law. KVL states that the total voltage drops around the loop in any closed electric circuit is equal to the sum of total voltage drop in the same closed loop.
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Question
Transcribed Image Text:Find the current passed
through 5 ohm resistor from
from point v1 to v2 that come
from each current source
1Ω
V3
4Ω
V4
1 A
5Ω
wwH 2
ЗА
10 N
2 A
O I(1A) =-1A I(2A) =-2A I(3A) =3A
None of the mentioned
O I(1A) =-1A I(2A) =-2A I(3A) =1.3A
O I(1A) =-1A I(2A) =-2A I(3A) =0A
O I(1A) =1A I(2A) =2A I(3A) =3A
O I(1A) =-1A I(2A) =-2A I(3A) =1A
O I(1A) =1A I(2A) =2A I(3A) =0A
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