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Apply KVL around P 6.₁ Answers i,= -7.5A 12 -2.5A 13 = 3.92 A 14 = 2.14 A io = -14 = -2.14 A r 1 5A 1 i ² L - Super Apply KVL on mesh 4 22 Apply KCL at node P Apply KCL at node Q Super mesh mesh 1 1 - 45 www Q - 1 √7310 (is 1380 (in 25 www 6i₂ + 21, +4₂ +8i, -8 i = 0 21, +6₂ +12, -8i =0 8₁₂-81₂ +21 + 10 = 0 4 i₁ +3₁₂ +6i₂ - 4₁₂ = 0 -(1) 10 ₁₁ -8 ₁ = -10 is i ₂ 3 i₂=5+1 (3) 3₁₁ + 1₂ = 1₂ 3 1. - 3₁₁ + 1₂ = 1₂ Tio - HOV -4₁, +5=-5-(2) 1₂ = 1₂ +3₁₂ — (4)

Apply KVL around P 6.₁ Answers i,= -7.5A 12 -2.5A 13 = 3.92 A 14 = 2.14 A io = -14 = -2.14 A r 1 5A 1 i ² L - Super Apply KVL on mesh 4 22 Apply KCL at node P Apply KCL at node Q Super mesh mesh 1 1 - 45 www Q - 1 √7310 (is 1380 (in 25 www 6i₂ + 21, +4₂ +8i, -8 i = 0 21, +6₂ +12, -8i =0 8₁₂-81₂ +21 + 10 = 0 4 i₁ +3₁₂ +6i₂ - 4₁₂ = 0 -(1) 10 ₁₁ -8 ₁ = -10 is i ₂ 3 i₂=5+1 (3) 3₁₁ + 1₂ = 1₂ 3 1. - 3₁₁ + 1₂ = 1₂ Tio - HOV -4₁, +5=-5-(2) 1₂ = 1₂ +3₁₂ — (4)

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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Can you please explain the steps to get the current values i1 , i2 , i3 , i4.

I already got the 4 equations needed but cannot get the correct values of the currents.

Answers are on the left bottom corner.

3 AA P 6.₁3 Answers 1₁ = -7.5 A 1₂ = -2.5A r 1 iz = 3.92 A 14 = 2.14 A io = 1+ = -2.14 A 1 5A i ² L Apply KVL around super mesh Apply KVL on mesh 4 22 Apply KCL at node P Apply KCL at node Q F Super mesh 1 1 L 1 - √310 - 40 www Q S fis 6₁₂ +21₁ + 4i₂ + 8iz - 8 i = 0 2₁₁ + 6₁₂ + 1² ₁₂ - 8i = 0 ។ 1 8₁₁ -8 ₂ + 2 1₂ + ¹0 = 0 iz 31₁ + 1₁ = 10 iz 3 4 20 ww Tio 13822 fir 10V 10 ₁₁ -8 ₁ = -10 14 13 1₂ = 5 + 1₁ (3) 2 3 1₁ + 3i₂ +6 i ₂ - 4 ₁ ₂ = 0 - ( - - 4 ₁₂ + 5₁₁₂ = −5 − (2) RE 2 5.
Transcribed Image Text:3 AA P 6.₁3 Answers 1₁ = -7.5 A 1₂ = -2.5A r 1 iz = 3.92 A 14 = 2.14 A io = 1+ = -2.14 A 1 5A i ² L Apply KVL around super mesh Apply KVL on mesh 4 22 Apply KCL at node P Apply KCL at node Q F Super mesh 1 1 L 1 - √310 - 40 www Q S fis 6₁₂ +21₁ + 4i₂ + 8iz - 8 i = 0 2₁₁ + 6₁₂ + 1² ₁₂ - 8i = 0 ។ 1 8₁₁ -8 ₂ + 2 1₂ + ¹0 = 0 iz 31₁ + 1₁ = 10 iz 3 4 20 ww Tio 13822 fir 10V 10 ₁₁ -8 ₁ = -10 14 13 1₂ = 5 + 1₁ (3) 2 3 1₁ + 3i₂ +6 i ₂ - 4 ₁ ₂ = 0 - ( - - 4 ₁₂ + 5₁₁₂ = −5 − (2) RE 2 5.
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