Find the critical value to for the confidence level c = 0.90 and sample size n = 14. Click the icon to view the t-distribution table. (Round to the nearest thousandth as needed.)
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Q: Use the confidence interval to find the margin of error and the sample mean. (0.676,0.800)
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A: Given,
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- A doctor wants to estimate the mean HDL cholesterol of all 20- to 29-year-old females. How many subjects are needed to estimate the mean HDL cholesterol within 3 points with 99% confidence assuming s = 12.5 based on earlier studies? Suppose the doctor would be content with 90% confidence. How does the decrease in confidence affect the sample size required? E Click the icon to view a partial table of critical values. A 99% confidence level requires subjects. (Round up to the nearest subject.) Tutoring Help me solve this Get more help- Clear all Check answer MacBook Pro ** esc G Search or type URL @ # $ % & 7 8. delete 1 2 3 4 Q W E R Y P 11 G H J KUse the confidence interval to find the margin of error and the sample mean. (1.59,1.95) The margin of error is (Round to two decimal places as needed.)You are a data analyst for a health insurance company and want to estimate the population mean of the surgery durations for all heart valve patients. To do so, you select a random sample of 32 heart valve surgery patients, and you record the surgery duration for each. Assume it is known that the population standard deviation of the durations of all heart valve surgeries is 1.92 hours. Based on your sample, follow the steps below to construct a 99% confidence interval for the population mean of the surgery durations for all heart valve patients. (If necessary, consult a list of formulas.) (a) Click on "Take Sample" to see the results from your random sample of 32 heart valve patients. (b) Take Sample Sample size: 0 Point estimate: 0 Population standard deviation: 0 Critical value: 0 Compute 0.00 0.00 Number of patients 32 Enter the values of the sample size, the point estimate for the population mean, the population standard deviation, and the critical value you need for your 99%…
- One year, the mean age of an inmate on death row was 40.1 years. A sociologist wondered whether the mean age of a death-row inmate has changed since then. She randomly selects 32 death-row inmates and finds that their mean age is 39.3, with a standard deviation of 9.9. Construct a 95% confidence interval about the mean age. What does the interval imply? Click the icon to view the table of critical t-values. C Choose the correct hypotheses. Ho: ▼ H₁₂: (Type integers or decimals. Do not round.) Construct a 95% confidence interval about the mean age. years and years. (Round to two decimal places as needed.) With 95% confidence, the mean age of a death row inmate is between What does the interval imply? O A. Since the mean age from the earlier year is not contained in the interval, there is not sufficient evidence to conclude that the mean age had changed. O B. Since the mean age from the earlier year is contained in the interval, there is sufficient evidence to conclude that the mean age…Determine the critical values for the confidence interval for the population variance from the given values. Round your answers to three decimal places. n = 22 and a = 0.02.Heights for teenage boys and girls were calculated. The mean height for the sample of 47 boys was 185 cm and the variance was 58. For the sample of 66 girls, the mean was 174 cm and the variance was 69. There is no reason to assume the variances would be equal. Estimate how much taller teenage boys are using a 87% confidence level. Express this in the (point estimate) ± (margin of error) format. Round answers to 2 decimal places. H
- The graph below shows a 95% confidence interval for a population proportion that has been estimated as 0.5. Move the slider below the graph to change the number of observations in the sample and observe how it affects the equation for the interval and the corresponding interval width. P(1-p) pt Za/2V 0.5 + 1.961 0.5(1-0.5) 1276 95% Cl: 0.5 ± 0.0274 = [0.4726, 0.5274] -0.0274 +0.0274 0.45 0.4726 0.50 0.5274 0.55 n = 1276 1,000 2,000 1. In the equation for a confidence interval, the sample size is located in the denominator underneath the radical sign. What happens to the value of the expression under the radical sign as the sample size increases? a. The value of everything under the radical sign remains the same. b. The value of everything under the radical sign increases. c. The value of everything under the radical sign decreases. -Select- vA sample of 19 Math SAT scores for women was collected. The mean score for the sample was 496 and the sample standard deviation was 115. Find the 95% confidence interval for the population mean µ. Assume the population has a normal distribution. Confidence Interval: ( Enter numbers correct to one unit.Use the standard normal distribution or the t-distribution to construct a 90% confidence interval for the population mean. Justify your decision. If neither distribution can be used, explain why. Interpret the results. In a random sample of 40 people, the mean body mass index (BMI) was 26.6 and the standard deviation was 6.13.
- Calculate the margin of error of a confidence interval for the difference between two population means using the given information. Round your answer to six decimal places. σ1=4.52 , n1=113, σ2=7.72, n2=105, c=0.95Now change the 'Normal' choice to 'Exponential' This changes the underlying population from one that has a normal distribution to one that is very not normal. Change the sample size to 5 and run samples. a. How well do the 95% confidence intervals do at capturing the true population mean when samples sizes are small? b. Now change the sample size to 40 and run samples. Does a larger sample size mean that the intervals are more likely to capture the true population value? Why? Note THIS is an important concept and relates back to the Sampling Distribution of Sample Means and how the SDSM changes as sample size increases when the population is not normal.Use the Student's t distribution to find tc for a 0.95 confidence level when the sample is 3. (Round your answer to three decimal places.) USE SALT
