Use the confidence interval to find the margin of error and the sample mean. (1.52,1.90) ... The margin of error is (Round to two decimal places as needed.)
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- Use the given confidence interval to find the margin of error and the sample mean. (70.5,84.7)Use the given confidence interval to find the margin of error and the sample mean. (71.7, 87.3)Use the confidence interval to find the margin of error and the sample mean. (0.614,0.690) The margin of error is The sample mean is
- Use the given confidence interval to find the margin of error and the sample mean. (4.81, 8.09)Im confused on #1.) Letter C. I already found the 68% range and the 95% range by using the empirical rule. Now it is asking " What percentage of this sample fall bellow 90? With the mean of 78 and standard deviation of 6.May I please get help with this question? Given the interval estimate for the mean (8.6, 12.4), the point estimate for the mean is , and the margin of error is .
- n= 1655 (nubers of tries), x=176 (number of success tries), 98% confidence. Find the confidence interval estimate of the population proportion p.Use the confidence interval to find the estimated margin of error. Then find the sample mean. A store manager reports a confidence interval of (48.1,78.7) when estimating the mean price (in dollars) for the population of textbooks. The estimated margin of error is?Use the confidence interval to find the margin of error and the sample mean. (0.346,0.450) The margin of error is The sample mean is 9 五 0 SF10