Find the critical value t, for the confidence level c = 0.90 and sample size n= 15.t-Distribution TableClick the icon to view the t-distribution table.Level oft =(Round to the nearest thousandth as needed.)confidence, cOne tail, aTwo tails, a0.800.900.950.980.990.100.050.0250.010.005d.f.0.200.100.050.020.01d.f.3.0786.31412,70631.8216 965163.657121.8862.9204.3036.9659.92533.1824.5415.84121931.6382.3533 74741.5332.1322.7763.747A.60441.4762.0152.5712 7653.3654.03261.4401.9432.4473.1433.7076.1.4151.8952.3652.9982 4003.49978.1,3971.8602.3062.8963.3558.9.1.3831.8332.2622.8213.250101.3721.8122.2282.7643.169101.3631.3561.350111.7962.2012.7183.10611121.7822.1792.6813.05512131.7712,1602.6503.01213141.3451.7612,1452.6242.97714151.3411.7532.1312.6022.94715

Name: Find the critical value t, for the confidence level c = 0.90 and samp
Uploaded: 2024-03-20T07:07:12.000Z
Channel: Bartleby
Description: Find the critical value t, for the confidence level c = 0.90 and sample size n= 15.t-Distribution TableClick the icon to view the t-distribution table.Level oft =(Round to the nearest thousandth as needed.)confidence, cOne tail, aTwo tails, a0.800.9

Given data, n=15 C=0.90α=1-C =1-0.90 =0.10df=n-1=15-1=14α=0.10t-critical value at df=14 and α=0.10 is 1.761

Math

Statistics

Find the critical value t, for the confidence levelc = 0.90 and sample size n= 15. 1 t-Distribution Table Click the icon to view the t-distribution table. Level of t,= ] (Round to the nearest thousandth as needed.) confidence, c One tail, a Two tails, a 0.98 0.01 0.80 0.90 0.05 0.10 0.95 0.025 0.05 0.99 0.005 0.10 d.f. 0.20 0.02 0.01 d.f. 1 3.078 6.314 12.706 31.821 63.657 1 1.886 2.920 2.353 4.303 6.965 9.925 2 5.841 4.604 1.638 3.182 4.541 3 2.776 2.571 1.533 2.132 3.747 4 1.476 2.015 3.365 4.032 5 6. 1.440 1.943 2.447 3.143 3.707 6. 7. 1.415 1.895 2.365 2.998 3.499 7 8. 1.397 1.860 2.306 2.896 3.355 8 1.383 1.833 2.262 2.821 3.250 9 2.764 2.718 2.681 3.169 3.106 3.055 10 1.372 1.812 2.228 10 11 1.363 1.796 2.201 11 12 1.356 1.782 2.179 12 13 1.350 1 345 1.771 2.160 2.650 3.012 13 14 1 761 2145 2624 2077 14

Find the critical value t, for the confidence levelc = 0.90 and sample size n= 15. 1 t-Distribution Table Click the icon to view the t-distribution table. Level of t,= ] (Round to the nearest thousandth as needed.) confidence, c One tail, a Two tails, a 0.98 0.01 0.80 0.90 0.05 0.10 0.95 0.025 0.05 0.99 0.005 0.10 d.f. 0.20 0.02 0.01 d.f. 1 3.078 6.314 12.706 31.821 63.657 1 1.886 2.920 2.353 4.303 6.965 9.925 2 5.841 4.604 1.638 3.182 4.541 3 2.776 2.571 1.533 2.132 3.747 4 1.476 2.015 3.365 4.032 5 6. 1.440 1.943 2.447 3.143 3.707 6. 7. 1.415 1.895 2.365 2.998 3.499 7 8. 1.397 1.860 2.306 2.896 3.355 8 1.383 1.833 2.262 2.821 3.250 9 2.764 2.718 2.681 3.169 3.106 3.055 10 1.372 1.812 2.228 10 11 1.363 1.796 2.201 11 12 1.356 1.782 2.179 12 13 1.350 1 345 1.771 2.160 2.650 3.012 13 14 1 761 2145 2624 2077 14

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

calculate the 95% confidence interval for the mean stock price of the firm assuming that the stock price is normally distibuted.
You want to estimate the mean weight of quarters in circulation. A sample of 40 quarters has a mean weight of 5.626 grams and a standard deviation of 0.059 gram. Use a single value to estimate the mean weight of all quarters. Also, find the 95% confidence interval for the average weight of all quarters. The estimate for the mean weight of all quarters is (Round to three decimal places as needed.) an example Get more help - grams. Clear all
Find the critical value and rejection region.
A researcher wants to estimate the mean blood cholesterol level of young men ages 15-25 with a 90.16% confidence interval. The blood cholesterol level of young men follows a Normal distribution with standard deviation σ = 15 mg/dl. How large a sample would the researcher need to take to estimate the mean blood cholesterol to within 7 mg/dl? A sample of at least______people
Calculate the margin of error and construct the confidence interval for the population mean using the Student's t-distribution (you may assume the population data is normally distributed). T-Distribution Table a. x 88.2, n = 69, s 17.9, 98% confidence = E Round to two decimal places if necessary EAPA SAMSUNG SUBMIT QUESTION SAVE PROGRESS SUBT
00 7 In a random sample of six mobile devices, the mean repair cost was $90.00 and the standard deviation was $12.00. Assume the population is normally distributed and use a t-distribution to find the margin of error and construct a 99% confidence interval for the population mean. Interpret the results. The 99% confidence interval for the population mean u is ( D. (Round to two decimal places as needed.) Enter your answer in the edit fields and then click Check Answer. parts 2. remaining Clear All Check Answer P Type here to search 查 0 F1 F2 F3 PrtScn Ho F4 F5 F8 #3 & 24 2. 4. 5. C. B. Alt
z Scores LeBron James, one of the most successful basketball players of all time, has a height of 6 feet 8 inches, or 203 cm. Based on statistics from Data Set 1 “Body Data” in Appendix B, his height converts to the z score of 4.07. How many standard deviations is his height above the mean?