007In a random sample of six mobile devices, the mean repair cost was $90.00 and the standard deviation was $12.00. Assume the population isnormally distributed and use a t-distribution to find the margin of error and construct a 99% confidence interval for the population mean. Interpret theresults.The 99% confidence interval for the population mean u is ( D.(Round to two decimal places as needed.)Enter your answer in the edit fields and then click Check Answer.parts2.remainingClear AllCheck AnswerP Type here to search查 0F1F2F3PrtScnHoF4F5F8#3&242.4.5.C.B.Alt

Here it is given that - Total number of sample (n) = 6 Sample mean (x¯) = 90 Sample standard…

Answered: 00 7 In a random sample of six mobile…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Tina catches a 14-pound bass. She does not know the population mean or standard deviation. So she takes a sample of five friends and they say the last bass they caught was 9, 12, 13, 10, and 10 pounds. Find the t and calculate a 95% (α = .05) confidence interval.
Pearson's coefficient of skewness for a distribution is 0.4 and coefficient of variation is30%. Its mode is 88. Find the mean and the median.
Find the indicated IQ score. The graph to the right depicts IQ scores of adults, and those scores are normally distributed with a mean of 100 and a standard deviation of 15.
Construct the confidence interval for the population mean. If the sample size is 35, the sample mean is 4.8, and the sample standard deviation is 2.2. We also know that the population standard deviation is 2.6. Use the Confidence Level = 95%. Use parentheses and four decimal places.
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I was wondering if these answers are correct. Explain. A study by Quadrant Information Services commissioned by Insure.com calculated auto insurance rates for each of the 50 states; and as a result, the average annual rate for the United States was $1,317. Suppose annual rates of auto insurance in the United States are normally distributed with a standard deviation of $324. According to MoneyGeek, a state minimum auto insurance policy in Florida costs an average of $1123 per year and the average cost of full coverage car insurance in Florida is $2208. What percentage of policies cost less than the Florida state minimum policy of $1123? z = (x - mu) / sigma z = (1123-1317)/324 z= -0.59876543 P-value from Z-Table: P(x<1123) = 0.27466 The answer is less than I expected. After using a z-table to determine the score it results in 27% of policies that are less than the minimum policy of 1123. What percentage of auto insurance rates would be less than $1,200? z = (x - mu) / sigma…
The 95% confidence interval of the variance of a population is computed as (12.367,21.761). Interpret this confidence interval.
Follow the instructions in the given image and write all formulas to do the steps in the Excel.. Please only do the B part
For an Economics test the mean score is 100 and the standard deviation is 10, and for an Accounting test the mean score is 50 and the standard deviation is 4. You are given the test scores of a student who took both tests. Determine on which test the student had a better score. Enter E if the student did better on the Economics test Enter A if the student did better on the Accounting test Enter S if the student did relatively the same on both tests. A student scores 125.6 on the Economics test and 60.2 on the Accounting test. The student did better/same on test.
number 2 table only
A Moving to another question will save this response. Question 5 The national scores on an exam were normal distributed with a mean of 428 and a standard deviation of 113. Approximately what percent of those taking this test had scores between 315 and 541? A Moving to another question will save this response. Session 10 GN.docx MacBook Pro
You know the mean and standard deviation of the population. You take a sample from this population and compute the 90% confidence interval for the mean. This interval contains values that are within how many standard deviations of the mean?

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