Find the components at and an of the acceleration vector of a particle moving along the circular path of radius R = 10 cm wit constant velocity vo = 3 cm/s. (Use symbolic notation and fractions where needed.) at = an = 2 cm/s cm/s 2

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Chapter1: Units, Trigonometry. And Vectors
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### Problem Statement

Find the components \( a_T \) and \( a_N \) of the acceleration vector of a particle moving along the circular path of radius \( R = 10 \) cm with constant velocity \( v_0 = 3 \) cm/s.

(Use symbolic notation and fractions where needed.)

### Solution

**Tangential Acceleration Component (\( a_T \)):**

\[ a_T = \hspace{15em} \text{cm/s}^2 \]

**Normal Acceleration Component (\( a_N \)):**

\[ a_N = \hspace{15em} \text{cm/s}^2 \]

### Explanation

- **Tangential Acceleration (\( a_T \))**: This component of the acceleration is responsible for the change in the speed of the particle along the path. For a particle moving with a constant speed, the tangential acceleration is zero.

- **Normal Acceleration (\( a_N \))**: This component is directed towards the center of the circular path and is responsible for changing the direction of the velocity. It is also known as centripetal acceleration and can be calculated using the formula:
  
  \[
  a_N = \frac{v_0^2}{R}
  \]

Substitute the given values \( v_0 = 3 \) cm/s and \( R = 10 \) cm into the formula to find \( a_N \):

  \[
  a_N = \frac{(3 \text{ cm/s})^2}{10 \text{ cm}} = \frac{9 \text{ cm}^2/\text{s}^2}{10 \text{ cm}} = 0.9 \text{ cm/s}^2
  \]

### Final Values

\[ a_T = 0 \text{ cm/s}^2 \]

\[ a_N = 0.9 \text{ cm/s}^2  \]
Transcribed Image Text:### Problem Statement Find the components \( a_T \) and \( a_N \) of the acceleration vector of a particle moving along the circular path of radius \( R = 10 \) cm with constant velocity \( v_0 = 3 \) cm/s. (Use symbolic notation and fractions where needed.) ### Solution **Tangential Acceleration Component (\( a_T \)):** \[ a_T = \hspace{15em} \text{cm/s}^2 \] **Normal Acceleration Component (\( a_N \)):** \[ a_N = \hspace{15em} \text{cm/s}^2 \] ### Explanation - **Tangential Acceleration (\( a_T \))**: This component of the acceleration is responsible for the change in the speed of the particle along the path. For a particle moving with a constant speed, the tangential acceleration is zero. - **Normal Acceleration (\( a_N \))**: This component is directed towards the center of the circular path and is responsible for changing the direction of the velocity. It is also known as centripetal acceleration and can be calculated using the formula: \[ a_N = \frac{v_0^2}{R} \] Substitute the given values \( v_0 = 3 \) cm/s and \( R = 10 \) cm into the formula to find \( a_N \): \[ a_N = \frac{(3 \text{ cm/s})^2}{10 \text{ cm}} = \frac{9 \text{ cm}^2/\text{s}^2}{10 \text{ cm}} = 0.9 \text{ cm/s}^2 \] ### Final Values \[ a_T = 0 \text{ cm/s}^2 \] \[ a_N = 0.9 \text{ cm/s}^2 \]
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