Find the center-radius form of the equation of the circle. 21) center (-/3, -7), radius 3 A) (x - V3)2 + (y - 72 = 3 C) (x -V3)2 + (y – 72 = 9 B) (x + /3)2 + (y + 7)2 = 3 D) (x +/3)2 + (y + 7)2 = 3

Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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Find the center-radius form of the equation of the circle.
21) center (-/3, -7), radius 3
A) (x - 3)2 + (y --72 = 3
C) (x-3)2 + (y - 72 =9
21)
B) (x +/3)2 + (y + 7)2 = 3
D) (x +/3)2 + (y + 7)2 =3
Transcribed Image Text:Find the center-radius form of the equation of the circle. 21) center (-/3, -7), radius 3 A) (x - 3)2 + (y --72 = 3 C) (x-3)2 + (y - 72 =9 21) B) (x +/3)2 + (y + 7)2 = 3 D) (x +/3)2 + (y + 7)2 =3
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