find the center of mass of a Triangular Lamina Uniform distribution as bellow :
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A: Mass of bullet (m) = 5 g Mass of woodden block (m') = 1 kg Length of string (L) = 2 m h = 0.45 cm
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find the center of mass of a Triangular Lamina Uniform distribution as bellow :
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- Calculate the location of the center of mass of my arm as a distance from my shoulder if my arm is outstretched horizontally. My upper arm is 0.3m long, has a mass of 4 kg, and has a center of mass location of 0.15m from the shoulder. My forearm (includes hand) is 0.4m long, has a mass of 3 kg, and has a center of mass location of 0.2m from the elbow.Find the center of mass of the plate of uniform density with the following figure:In the figure, block 1 of mass m slides from rest along a frictionless ramp from height h-3.1 m and then collides with stationary block 2. which has mass m2 - 4m,. After the collision, block 2 slides into a region where the coefficient of kinetic friction is 0.5 and comes to a stop in distanced within that region. What is the value of distance dif the collision is (a) elastic and (b) completely inelastic? Frictionles (a) Number Unit (b) Number Unit
- Prove the following velocity relation for a head-on elastic collision between two particles:Water droplets, of mass m in each, are dripping from height h at a rate of r per second. Find the center of mass of the droplets.Problem #4: Consider a frictionless track as shown in the figure below. A block of mass m¡ = 4.00 kg is released from A. It makes a head-on elastic collision at B with a block of mass m2 = 20 kg that is initially at rest. Calculate the maximum height too which m¡ rises after the collision. 5.00 m m2 (B