Find the bubble point pressure and vapor composition for a liquid mixture of 41.2 mol % ethanol (1) and n-hexane (2) at 331°K.5 Data: Activity from Van Laar equations: A [1 + (Ax₁ / Bx₂)]³² A=2.409, and B = 1.970 Vapor pressure: (Psat in kPa and 7' in °K) In 11 = In P₁ sat = 16.1952- - 3423.53 T-55.7152 In 1/2 = B [1+ (Bx₂ / Ax₁)]² In P₂sat 14.0568 - 1 2825.42 T-42.7089
Find the bubble point pressure and vapor composition for a liquid mixture of 41.2 mol % ethanol (1) and n-hexane (2) at 331°K.5 Data: Activity from Van Laar equations: A [1 + (Ax₁ / Bx₂)]³² A=2.409, and B = 1.970 Vapor pressure: (Psat in kPa and 7' in °K) In 11 = In P₁ sat = 16.1952- - 3423.53 T-55.7152 In 1/2 = B [1+ (Bx₂ / Ax₁)]² In P₂sat 14.0568 - 1 2825.42 T-42.7089
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
Related questions
Question
![**Example #5:**
Find the bubble point pressure and vapor composition for a liquid mixture of 41.2 mol% ethanol (1) and n-hexane (2) at 331°K.
**Data: Activity from Van Laar equations:**
\[
\ln \gamma_1 = \frac{A}{\left[1 + \left( \frac{Ax_1}{Bx_2} \right) \right]^2}
\]
\[
\ln \gamma_2 = \frac{B}{\left[1 + \left( \frac{Bx_2}{Ax_1} \right) \right]^2}
\]
\[ A = 2.409, \text{ and } B = 1.970 \]
**Vapor pressure**: (\(P_i^{\text{sat}}\) in kPa and \(T\) in °K)
\[
\ln P_1^{\text{sat}} = 16.1952 - \frac{3423.53}{T - 55.7152}
\]
\[
\ln P_2^{\text{sat}} = 14.0568 - \frac{2825.42}{T - 42.7089}
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Transcribed Image Text:**Example #5:**
Find the bubble point pressure and vapor composition for a liquid mixture of 41.2 mol% ethanol (1) and n-hexane (2) at 331°K.
**Data: Activity from Van Laar equations:**
\[
\ln \gamma_1 = \frac{A}{\left[1 + \left( \frac{Ax_1}{Bx_2} \right) \right]^2}
\]
\[
\ln \gamma_2 = \frac{B}{\left[1 + \left( \frac{Bx_2}{Ax_1} \right) \right]^2}
\]
\[ A = 2.409, \text{ and } B = 1.970 \]
**Vapor pressure**: (\(P_i^{\text{sat}}\) in kPa and \(T\) in °K)
\[
\ln P_1^{\text{sat}} = 16.1952 - \frac{3423.53}{T - 55.7152}
\]
\[
\ln P_2^{\text{sat}} = 14.0568 - \frac{2825.42}{T - 42.7089}
\]
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