Consider a reversible isothermal expansion of vapor benzene at 450 K from 1 to 0.1 MPa. Assume that the PVT behavior of benzene obeys van der Waals equation of state.                                      P = (RT)/(V - b) - a/V2            for benzene: a = 1884514 (cm6 * MPa)/mol2 and                                  b = 119.47 cm3/mol For your convenience, at 450 K and 0.1 MPa the volume of vapor benzene is 37025 cm3/mol, and at 450 K and 1 MPa it is 3312.4 cm3/mol. R = 8.314 (MPa*cm3)/(mol*K). Note: 1 cm3*MPa/mol = 1 J/mol   Question: What is the change of internal energy? What would be the change of internal energy if the gas was ideal?

Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
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Consider a reversible isothermal expansion of vapor benzene at 450 K from 1 to 0.1 MPa. Assume that the PVT behavior of benzene obeys van der Waals equation of state.

                                     P = (RT)/(V - b) - a/V2

           for benzene: a = 1884514 (cm6 * MPa)/mol2 and

                                 b = 119.47 cm3/mol

For your convenience, at 450 K and 0.1 MPa the volume of vapor benzene is 37025 cm3/mol, and at 450 K and 1 MPa it is 3312.4 cm3/mol. R = 8.314 (MPa*cm3)/(mol*K).

Note: 1 cm3*MPa/mol = 1 J/mol

 

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What is the change of internal energy? What would be the change of internal energy if the gas was ideal?

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