Find the B-coordinate vector of x E H where B = {b₁,b₂} is a basis of subspace H. b₁ = H b₂ = [6] 3 2 x = 2 图

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
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**Problem Statement:**

Find the \(\mathcal{B}\)-coordinate vector of \( x \in H \) where \(\mathcal{B} = \{b_1, b_2\}\) is a basis of subspace \( H \).

**Given Vectors:**

\[ b_1 = \begin{bmatrix} 1 \\ -5 \\ -4 \end{bmatrix}, \quad b_2 = \begin{bmatrix} 3 \\ 3 \\ 2 \end{bmatrix}, \quad x = \begin{bmatrix} 5 \\ 2 \\ 1 \end{bmatrix} \] 

**Explanation:**
The task is to express vector \( x \) as a linear combination of the basis vectors \( b_1 \) and \( b_2 \). This involves finding scalars \( c_1 \) and \( c_2 \) such that:

\[ x = c_1 b_1 + c_2 b_2 \]

Solving this equation will give the \(\mathcal{B}\)-coordinate vector for \( x \).
Transcribed Image Text:**Problem Statement:** Find the \(\mathcal{B}\)-coordinate vector of \( x \in H \) where \(\mathcal{B} = \{b_1, b_2\}\) is a basis of subspace \( H \). **Given Vectors:** \[ b_1 = \begin{bmatrix} 1 \\ -5 \\ -4 \end{bmatrix}, \quad b_2 = \begin{bmatrix} 3 \\ 3 \\ 2 \end{bmatrix}, \quad x = \begin{bmatrix} 5 \\ 2 \\ 1 \end{bmatrix} \] **Explanation:** The task is to express vector \( x \) as a linear combination of the basis vectors \( b_1 \) and \( b_2 \). This involves finding scalars \( c_1 \) and \( c_2 \) such that: \[ x = c_1 b_1 + c_2 b_2 \] Solving this equation will give the \(\mathcal{B}\)-coordinate vector for \( x \).
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