find the angular speed of revolution of earth required so that the body on its surface at equator would feel no weight (r. 6400km. g -9.8m/s-2
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- The asteroid belt circles the sun between the orbits of Mars and Jupiter. One asteroid has a period of 5.0 earth years. Assume a 365.25-days year and MSun = 1.99 × 1030 kg. 1. What is the asteroid's orbital radius? Express your answer in two significant figures. 2. What is the asteroid's orbital speed? Express answer in two significant figures.It has been suggested that rotating cylinders about 10.5 mi long and 6.32 mi in diameter be placed in space and used as colonies. What angular speed must such a cylinder have so that the centripetal acceleration at its surface equals the free-fall acceleration on Earth? rad/s =An Earth satellite has its apogee at 2750 km above the surface of Earth and perigee at 490 km above the surface of Earth. At apogee its speed is 830 m/s. What is its speed at perigee? Earth's radius is 6378 km (see below). A M Vp
- 36. A satellite circles the earth in an orbit whose radius is twice the earth's radius. The earth's mass is 5.98 × 10ª kg, and its radius is 6.38 × 10º m. What is the period of the satellite?An athlete swings a 6.30-kg ball horizontally on the end of a rope. The ball moves in a circle of radius 0.690 m at an angular speed of 0.450 rev/s. What is the tangential speed of the ball? What is its centripetal acceleration? If the maximum tension the rope can withstand before breaking is 128 N, what is the maximum tangential speed the ball can have?An object weighs 90 N on Earth’s surface. Determine its weight when it is two Earth radii from the planet’s surface.
- 28. An elliptical orbit can be analyzed using conservation of angular momentum and mechanical energy. The distance between Earth, mass 5.972 × 1024 kg, and Sun, mass 1.989 × 1030 kg, varies from 147 to 152 Gm. (a) Use the formula UG = – Gm1m2/r to find the change in potential energy that occurs moving from the farthest distance to the nearest. (b) Given that the speed of Earth at its farthest point is 29.29 km/s, use conservation of energy to find its speed at the nearest point. (c) Calculate the angular momentum of Earth at each extreme and show that it is equal.29. Use concepts from the previous problem to find the speed of Pluto at each extreme of its orbit about the Sun – distance varying from 4.44 × 1012 m to 7.38 × 1012 m. Hint: use a system of equations based on conservation of energy and angular momentum. P.S. I already solved 28 but I don't know how to do 29.Scientists want to place a 2800 kg satellite in a circular orbit around Mars. They plarto have the satellite orbit at a speed of 2100 m/s. How far above the surface of Mars will the satellite orbit? Mmars = 6.5 x 10^23 kg mars = 3.40 x 10^6 m G= 6.67 x 10^-11 N-m2/kg?