**Understanding Neutron Stars and Their Rotation****Concept Overview:**Neutron stars are incredibly dense celestial objects formed from the remnants of supernova explosions. Due to their density, they possess unique properties, including the ability to spin rapidly. This text explores a scenario involving such a star to calculate its angular speed.**Problem Statement:**We are given a spherical neutron star with the following characteristics:- Mass: Twice that of the Sun.- Radius: 10.0 km.**Objective:**Determine the greatest possible angular speed at which the neutron star can rotate without causing the matter at its surface on the equator to break away from its gravitational force.**Solution Approach:**- Consider the balance between gravitational and centrifugal forces to ensure stability.- Use Newton's Law of Gravitation alongside rotational dynamics.- Equate these forces to solve for the angular speed that ensures matter on the equator remains in orbit without separating from the star’s gravitational influence.This educational exercise involves applying principles of physics, specifically mechanics and gravitational theory, to understand the behavior of astronomical phenomena under extreme conditions.

Answered: Image /qna-images/answer/3ac81394-2af5-46ea-ae5e-dead914a4a0e.jpg

Neutron stars are extremely dense objects that are formed from the remnants of supernova explosions. Many rotate very rapidly. Suppose the mass of a certain spherical neutron star is twice the mass of the Sun and its radius is 10.0 km. Determine the greatest possible angular speed the neutron star can have so that the matter at its surface on the equator is just held in orbit by the gravitational force.

Neutron stars are extremely dense objects that are formed from the remnants of supernova explosions. Many rotate very rapidly. Suppose the mass of a certain spherical neutron star is twice the mass of the Sun and its radius is 10.0 km. Determine the greatest possible angular speed the neutron star can have so that the matter at its surface on the equator is just held in orbit by the gravitational force.

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

See similar textbooks

Similar questions

Titan completes one orbit about Saturn in 15.9 days and the average Saturn-Titan distance is 1.22 x 10° m. Calculate the angular speed o of Titan as it orbits Saturn. rad/s =
A meteoroid is moving towards a planet. It has mass m = 0.54×109 kg and speed v1 = 4.7×107 m/s at distance R1 = 1.6×107 m from the center of the planet. The radius of the planet is R = 0.78×107 m. The mass of the planet is M = 5.6×1025kg. There is no air around the planet. a)Enter an expression for the total energy E of the meteoroid at R, the surface of the planet, in terms of defined quantities and v, the meteoroid’s speed when it reaches the planet’s surface. Select from the variables below to write your expression. Note that all variables may not be required.α, β, θ, d, g, G, h, m, M, P, R, R1, t, v, v1 b)Enter an expression for v, the meteoroid’s speed at the planet’s surface, in terms of G, M, v1, R1, and R. c)Calculate the value of v in meters per second.
Uranus has a mass of 8.68 x 1025 kg and a radius of 2.56 x 10 m. Assume it is a uniform solid sphere. The distance of Uranus from the Sun is 2.87 x 10¹2 m. (Assume Uranus completes a single rotation in 17.3 hours and orbits the Sun once every 3.08 x 104 Earth days.) (a) What is the rotational kinetic energy of Uranus on its axis? J (b) What is the rotational kinetic energy of Uranus in its orbit around the Sun? J
The evolution of a star depends on its size. If a star is sufficiently large, the gravity forces holding it together may be large enough to collapse it into a very dense object composed mostly of neutrons. The density of such a neutron star is about 1014 times that of the Earth. Suppose that a star initially had a radius of 7 x 108 km, and it rotated once every 26 days. What would be the period of rotation if the star collapsed to a radius of 15 km? (1.19 x 10-14 days)
White dwarf stars are produced by the collapse of regular stars, such as our sun, toward the end of their normal life. Suppose a star initially has the same mass as our sun and the same radius as that of the sun. Suppose further that it collapses into a white dwarf with a radius of 5000km. If the initial period of the star is the same 27 day period of our sun, what is the resulting period of the white dwarf?
Certain neutron stars (extremely dense stars) are believed to be rotating at about 1 rev/s. If such a star has a radius of 20 km, what must be its minimum mass so that material on its surface remains in place during the rapid rotation?
A star has a mass of 1.03 x 1030 kg and is moving in a circular orbit about the center of its galaxy. The radius of the orbit is 2.4 x 104 light-years (1 light-year = 9.5 x 1015 m), and the angular speed of the star is 1.0 x 10-15 rad/s. (a) Determine the tangential speed of the star. (b) What is the magnitude of the net force that acts on the star to keep it moving around the center of the galaxy?
PRINTER VERSION 4 ВАСК NEXT Chapter 13, Problem 079 A certain triple-star system consists of two stars, each of mass m = 4.8×1030 kg, revolving in the same circular orbit of radius r = 3.2x1011 m about a central star of mass M = 6.9x1033 kg (the figure). The two orbiting stars are always at opposite ends of a diameter of the orbit. Calculate the period of revolution of the stars. Number Units the tolerance is +/-2% Click if you would like to Show Work for this question: Open Show Work