Find the acceleration of gravity at the surface of Mars (gMars) & Pluto (geluto)- M Mars-6.4191x1023 kg; R Mars-3.376x10 m; G-6.67300x10-11 m³ / ( kg s² ) M Eluta =1.31x1022 kg; R Pluta =1.160x10 m; G-6.67300x10-11 m³ / ( kg s² )
Find the acceleration of gravity at the surface of Mars (gMars) & Pluto (geluto)- M Mars-6.4191x1023 kg; R Mars-3.376x10 m; G-6.67300x10-11 m³ / ( kg s² ) M Eluta =1.31x1022 kg; R Pluta =1.160x10 m; G-6.67300x10-11 m³ / ( kg s² )
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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![### Problem 8: Calculating Gravitational Acceleration on Mars and Pluto
**Objective:**
Find the gravitational acceleration at the surface of Mars \((g_{\text{Mars}})\) and Pluto \((g_{\text{Pluto}})\).
#### Given Data:
- **Mars:**
- Mass (\(M_{\text{Mars}}\)): \(6.4191 \times 10^{23}\) kg
- Radius (\(R_{\text{Mars}}\)): \(3.376 \times 10^{6}\) m
- **Pluto:**
- Mass (\(M_{\text{Pluto}}\)): \(1.31 \times 10^{22}\) kg
- Radius (\(R_{\text{Pluto}}\)): \(1.160 \times 10^{6}\) m
- **Gravitational Constant (\(G\)):**
- \(6.67300 \times 10^{-11} \, \text{m}^3/\text{kg}\,\text{s}^2\)
### Calculations:
The formula for gravitational acceleration \(g\) at the surface of a planet is:
\[
g = \frac{G \times M}{R^2}
\]
#### Gravitational Acceleration on Mars \((g_{\text{Mars}})\):
\[
g_{\text{Mars}} = \frac{6.67300 \times 10^{-11} \times 6.4191 \times 10^{23}}{(3.376 \times 10^{6})^2}
\]
#### Gravitational Acceleration on Pluto \((g_{\text{Pluto}})\):
\[
g_{\text{Pluto}} = \frac{6.67300 \times 10^{-11} \times 1.31 \times 10^{22}}{(1.160 \times 10^{6})^2}
\]
The above expressions can be computed to find the specific values for the gravitational accelerations.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F322ab9b5-8b73-42ca-a79a-5c7ee3611144%2Fdcbd3e47-ebf1-426a-95a2-1dbb79e29603%2F27wn07d_processed.jpeg&w=3840&q=75)
Transcribed Image Text:### Problem 8: Calculating Gravitational Acceleration on Mars and Pluto
**Objective:**
Find the gravitational acceleration at the surface of Mars \((g_{\text{Mars}})\) and Pluto \((g_{\text{Pluto}})\).
#### Given Data:
- **Mars:**
- Mass (\(M_{\text{Mars}}\)): \(6.4191 \times 10^{23}\) kg
- Radius (\(R_{\text{Mars}}\)): \(3.376 \times 10^{6}\) m
- **Pluto:**
- Mass (\(M_{\text{Pluto}}\)): \(1.31 \times 10^{22}\) kg
- Radius (\(R_{\text{Pluto}}\)): \(1.160 \times 10^{6}\) m
- **Gravitational Constant (\(G\)):**
- \(6.67300 \times 10^{-11} \, \text{m}^3/\text{kg}\,\text{s}^2\)
### Calculations:
The formula for gravitational acceleration \(g\) at the surface of a planet is:
\[
g = \frac{G \times M}{R^2}
\]
#### Gravitational Acceleration on Mars \((g_{\text{Mars}})\):
\[
g_{\text{Mars}} = \frac{6.67300 \times 10^{-11} \times 6.4191 \times 10^{23}}{(3.376 \times 10^{6})^2}
\]
#### Gravitational Acceleration on Pluto \((g_{\text{Pluto}})\):
\[
g_{\text{Pluto}} = \frac{6.67300 \times 10^{-11} \times 1.31 \times 10^{22}}{(1.160 \times 10^{6})^2}
\]
The above expressions can be computed to find the specific values for the gravitational accelerations.
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