An extrasolar planet has mass 1.27E+25_kg and radius 67400000_m. What is the escape speed for this planet? 11440.m/s В. 12230_m/s 5014_m/s А. D. 16190.m/s 1973.m/s 9206 m/s Е. С. F.
An extrasolar planet has mass 1.27E+25_kg and radius 67400000_m. What is the escape speed for this planet? 11440.m/s В. 12230_m/s 5014_m/s А. D. 16190.m/s 1973.m/s 9206 m/s Е. С. F.
College Physics
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ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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![**Problem Statement:**
An extrasolar planet has a mass of \(1.27 \times 10^{25}\) kg and a radius of 67,400,000 m. What is the escape speed for this planet?
**Answer Choices:**
A. 11,440 m/s
B. 12,230 m/s
C. 5,014 m/s
D. 16,190 m/s
E. 1,973 m/s
F. 9,206 m/s
**Explanation:**
To find the escape speed, use the formula:
\[ v_e = \sqrt{\frac{2GM}{R}} \]
Where:
- \( v_e \) = escape speed
- \( G \) = universal gravitational constant (\(6.674 \times 10^{-11} \, \text{m}^3 \text{kg}^{-1} \text{s}^{-2}\))
- \( M \) = mass of the planet (\(1.27 \times 10^{25} \, \text{kg}\))
- \( R \) = radius of the planet (67,400,000 m)
Substitute the values into the formula to calculate the escape speed.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F32d80c3f-e8ca-4b33-9136-508eae27e90c%2Fdbd560c9-8016-420d-8ceb-1bb568f99bc6%2Ff32gkgh_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Problem Statement:**
An extrasolar planet has a mass of \(1.27 \times 10^{25}\) kg and a radius of 67,400,000 m. What is the escape speed for this planet?
**Answer Choices:**
A. 11,440 m/s
B. 12,230 m/s
C. 5,014 m/s
D. 16,190 m/s
E. 1,973 m/s
F. 9,206 m/s
**Explanation:**
To find the escape speed, use the formula:
\[ v_e = \sqrt{\frac{2GM}{R}} \]
Where:
- \( v_e \) = escape speed
- \( G \) = universal gravitational constant (\(6.674 \times 10^{-11} \, \text{m}^3 \text{kg}^{-1} \text{s}^{-2}\))
- \( M \) = mass of the planet (\(1.27 \times 10^{25} \, \text{kg}\))
- \( R \) = radius of the planet (67,400,000 m)
Substitute the values into the formula to calculate the escape speed.
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