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Find the absolute minimum value on [0, o) for f(x)=x-6x+2. ...... Select the correct choice below and, if necessary, fill in the answer boxes to complete your choice. O A. The absolute minimum is at x = O B. There is no absolute minimum.

Find the absolute minimum value on [0, o) for f(x)=x-6x+2. ...... Select the correct choice below and, if necessary, fill in the answer boxes to complete your choice. O A. The absolute minimum is at x = O B. There is no absolute minimum.

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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**Question:** Find the absolute minimum value on \([0, \infty)\) for \( f(x) = x^2 - 6x + 2 \). **Instructions:** Select the correct choice below and, if necessary, fill in the answer boxes to complete your choice. - **Option A:** The absolute minimum is \(\_\_\_\) at \( x = \_\_\_\) - **Option B:** There is no absolute minimum. **User Interaction:** - Textbook - Ask my instructor **Explanation:** This problem asks you to determine the absolute minimum of the quadratic function \(f(x) = x^2 - 6x + 2\) over the interval \([0, \infty)\). You can find the vertex of the parabola, as it represents the minimum point for a parabola that opens upwards. If the vertex \(x\) is within the given interval, it is the absolute minimum. Otherwise, check the value at \(x=0\).
Transcribed Image Text:**Question:** Find the absolute minimum value on \([0, \infty)\) for \( f(x) = x^2 - 6x + 2 \). **Instructions:** Select the correct choice below and, if necessary, fill in the answer boxes to complete your choice. - **Option A:** The absolute minimum is \(\_\_\_\) at \( x = \_\_\_\) - **Option B:** There is no absolute minimum. **User Interaction:** - Textbook - Ask my instructor **Explanation:** This problem asks you to determine the absolute minimum of the quadratic function \(f(x) = x^2 - 6x + 2\) over the interval \([0, \infty)\). You can find the vertex of the parabola, as it represents the minimum point for a parabola that opens upwards. If the vertex \(x\) is within the given interval, it is the absolute minimum. Otherwise, check the value at \(x=0\).
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