Identify the function's extreme values in the given domain, and say where they are assumed. Tell which of the extreme values, if any, are absolute. f(x) = V36 –x², - 6sx< 6 .....

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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**Identify the function's extreme values in the given domain, and say where they are assumed. Tell which of the extreme values, if any, are absolute.**

Given function: \( f(x) = \sqrt{36 - x^2}, \quad -6 \leq x < 6 \)

**Options:**

- **A.** Local and absolute minimum: 0 at \( x = -6 \) and \( x = 6 \)  
  Local and absolute maximum: 6 at \( x = 0 \)

- **B.** Local and absolute minimum: 6 at \( x = 0 \)  
  Local and absolute maximum: 0 at \( x = -6 \)

- **C.** No local extrema  
  No absolute extrema

- **D.** Local and absolute minimum: 0 at \( x = -6 \)  
  Local and absolute maximum: 6 at \( x = 0 \)
Transcribed Image Text:**Identify the function's extreme values in the given domain, and say where they are assumed. Tell which of the extreme values, if any, are absolute.** Given function: \( f(x) = \sqrt{36 - x^2}, \quad -6 \leq x < 6 \) **Options:** - **A.** Local and absolute minimum: 0 at \( x = -6 \) and \( x = 6 \) Local and absolute maximum: 6 at \( x = 0 \) - **B.** Local and absolute minimum: 6 at \( x = 0 \) Local and absolute maximum: 0 at \( x = -6 \) - **C.** No local extrema No absolute extrema - **D.** Local and absolute minimum: 0 at \( x = -6 \) Local and absolute maximum: 6 at \( x = 0 \)
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